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Three identical cars A, B, and C are moving at the same speed on three bridges. Car A moves on a plane bridge, B on a convex bridge, and C on a concave bridge. FA, FB, and FC are the normal forces extorted by the cars on the bridges, then we can say that
  • a)
    FC is maximum
  • b)
    FB is maximum
  • c)
    FA  is maximum
  • d)
    FA = FB = FC
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Three identical cars A, B, and C are moving at the same speed on three...
When a body moves along a curved path a net force acts on the body that is directed towards the center of curvature. This force is called the centripetal Force, FC
FC = mV2/r
where, m is body mass, V is magnitude of the velocity, r is radius of curvature.

Calculation:
Given:
Case 1:
The car A is running on a plane bridge as shown -

The normal force FA = mg 
Case 2:-
The car B is running on a convex bridge as shown - 

Now this is a case of plane circular motion and in this case, the net centripetal force acts towards the center of curvature.
So the normal force

Case 3:
The car C is running on a concave bridge as shown - 

In this case, there is also a net centripetal force acting towards the center of curvature.
So the normal force FC

Hence, by looking at all three equations,
FC > FA > FB 
we can say that the contact force FC is the maximum among all three forces.
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Three identical cars A, B, and C are moving at the same speed on three bridges. Car A moves on a plane bridge, B on a convex bridge, and C on a concave bridge. FA, FB, and FC are the normal forces extorted by the cars on the bridges, then we can say thata)FC is maximumb)FB is maximumc)FA is maximumd)FA = FB = FCCorrect answer is option 'A'. Can you explain this answer?
Question Description
Three identical cars A, B, and C are moving at the same speed on three bridges. Car A moves on a plane bridge, B on a convex bridge, and C on a concave bridge. FA, FB, and FC are the normal forces extorted by the cars on the bridges, then we can say thata)FC is maximumb)FB is maximumc)FA is maximumd)FA = FB = FCCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Three identical cars A, B, and C are moving at the same speed on three bridges. Car A moves on a plane bridge, B on a convex bridge, and C on a concave bridge. FA, FB, and FC are the normal forces extorted by the cars on the bridges, then we can say thata)FC is maximumb)FB is maximumc)FA is maximumd)FA = FB = FCCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three identical cars A, B, and C are moving at the same speed on three bridges. Car A moves on a plane bridge, B on a convex bridge, and C on a concave bridge. FA, FB, and FC are the normal forces extorted by the cars on the bridges, then we can say thata)FC is maximumb)FB is maximumc)FA is maximumd)FA = FB = FCCorrect answer is option 'A'. Can you explain this answer?.
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