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For a prism of prism angle θ = 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥ n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?
- a)The value of Δe (in radians) is greater than that of Δn.
- b)Δe is proportional to Δn.
- c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.
- d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.
Correct answer is option 'B,C'. Can you explain this answer?
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Most Upvoted Answer
For a prism of prism angle θ= 60°, the refractive indices of...
Diagram at minimum deviation for n1 = n2 = n
n = 1.5
r1 = r2 = θ/2 = 30°
For face AQ,
n sin r2 = sin e
When n2 is given small variation, there will be no change in path of light ray inside prism.
As deviation on face AC is zero,
r2 = 30°
Now, for face AQ,
n2 sin 30° = sin e
For small change in n2, change in e is given by:
dn2 sin 30° = cos e de
Or dn2 = Δn de = Δe
Δn sin 30° = cos e Δe
Hence, option (2) is correct.
Hence, option (3) is correct.
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Community Answer
For a prism of prism angle θ= 60°, the refractive indices of...
Diagram at minimum deviation for n1 = n2 = n
n = 1.5
r1 = r2 = θ/2 = 30°
For face AQ,
n sin r2 = sin e
When n2 is given small variation, there will be no change in path of light ray inside prism.
As deviation on face AC is zero,
r2 = 30°
Now, for face AQ,
n2 sin 30° = sin e
For small change in n2, change in e is given by:
dn2 sin 30° = cos e de
Or dn2 = Δn de = Δe
Δn sin 30° = cos e Δe
Hence, option (2) is correct.
Hence, option (3) is correct.
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For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer?
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For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer?.
For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer?.
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For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer?, a detailed solution for For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer? has been provided alongside types of For a prism of prism angle θ= 60°, the refractive indices of the left half and the right half are, respectively, n1 and n2 (n2 ≥n1) as shown in the figure. The angle of incidence i is chosen such that the incident light rays will have minimum deviation if n1 = n2 = n = 1.5. For the case of unequal refractive indices, n1 = n and n2 = n + Δn (where Δn << n), the angle of emergence e = i + Δe. Which of the following statements is/are correct?a)The value of Δe (in radians) is greater than that of Δn.b)Δe is proportional to Δn.c)Δe lies between 2.0 and 3.0 milliradians, if Δn = 2.8 x 10-3.d)Δe lies between 1.0 and 1.6 milliradians, if Δn = 2.8 x 10-3.Correct answer is option 'B,C'. Can you explain this answer? theory, EduRev gives you an
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