Mechanical Engineering Exam  >  Mechanical Engineering Questions  >  A particle moves in a straight line. Its posi... Start Learning for Free
A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will be
  • a)
    12 m/s
  • b)
    6 m/s
  • c)
    24 m/s
  • d)
    48 m/s
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A particle moves in a straight line. Its position is defined by the eq...
The velocity of the particle is defined as the rate of change of its displacement and can be expressed as
v = dx/dt
whereas, the speed of the particle at any instance is given as the rate of change of its distance.
for maximum velocity 
dv/dt = 0
Calculation:
Given :
Position: x= 6t2 - t3
dx/dt = V = 12t - 3t2   ...(i)
and for maximum velocity 
dv/dt = 0,
dv/dt = 12-6t = 0 or 6t = 12 or t = 2 sec
Substitute this value of t in the (i) 
we get v = 12× 2 - 3× 22 = 12 m/sec
Free Test
Community Answer
A particle moves in a straight line. Its position is defined by the eq...
The equation x = 6t^2 describes the position of the particle in terms of time, t.

In this equation, x represents the position of the particle and t represents the time elapsed. The position of the particle changes as time progresses. The function 6t^2 describes how the position changes with time.

To find the position of the particle at a specific time, substitute the value of t into the equation. For example, if t = 2, then x = 6(2)^2 = 6(4) = 24. This means that the particle's position at t = 2 is 24.

The equation x = 6t^2 describes the motion of the particle in a straight line. As time increases, the position of the particle increases quadratically. This means that the particle is accelerating, as the position changes at an increasing rate.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer?
Question Description
A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A particle moves in a straight line. Its position is defined by the equation x = 6t2 − t3 where t in seconds and x is in meters. The maximum velocity of the particle during its motion will bea)12 m/sb)6 m/sc)24 m/sd)48 m/sCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
Explore Courses for Mechanical Engineering exam

Top Courses for Mechanical Engineering

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev