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A Particle is dropped from a height of 3 m on a horizantal floor, which has a coefficient of restitution with the ball of 1/2. The height to which the hall will rebound after striking the floor is
  • a)
    0.5 m
  • b)
    0.75 m
  • c)
    1.0 m
  • d)
    1.5 m
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A Particle is dropped from a height of 3 m on a horizantal floor, whic...
Given:
- Initial height of the particle = 3 m
- Coefficient of restitution of the ball with the floor = 1/2

To find:
- The height to which the ball will rebound after striking the floor

Explanation:

1. Coefficient of restitution:
The coefficient of restitution (e) is a measure of the ability of a ball to bounce back after a collision. It is defined as the ratio of the relative velocity of separation to the relative velocity of approach between two colliding bodies.

Mathematically, e = (v2f - v1f) / (v1i - v2i)

Where,
- v1i and v2i are the initial velocities of the two bodies before collision
- v1f and v2f are the final velocities of the two bodies after collision

In this case, the ball is dropped from a height, so its initial velocity is zero.

2. Calculation:
When the ball is dropped from a height of 3 m, it falls freely under the influence of gravity. As it hits the floor, it comes to a stop momentarily and then rebounds.

The rebound height can be calculated using the equation:

h = e^2 * H

Where,
- h is the rebound height
- e is the coefficient of restitution
- H is the initial height

Substituting the given values:
h = (1/2)^2 * 3
h = 1/4 * 3
h = 3/4
h = 0.75 m

3. Answer:
The height to which the ball will rebound after striking the floor is 0.75 m. Therefore, the correct answer is option B.
Free Test
Community Answer
A Particle is dropped from a height of 3 m on a horizantal floor, whic...
If a ball is dropped from a height ho on a horizontal floor, then it strikes with the floor with a speed,

and it rebounds from the floor with a speed, 

Where, Coefficient of restitution = 
First height of rebound, 


Therefore,
The velocity of ball after nth rebound; Vn = enVo
The height of ball  after nth rebound,  hn = e2nho
Calculation: 
Given: ho = 3 m., e = 0.5, h1 = ?
We know that, height after first rebound: 
h1 = (0.5)2 × 3 = 0.75 m.
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A Particle is dropped from a height of 3 m on a horizantal floor, which has a coefficient of restitution with the ball of 1/2. The height to which the hall will rebound after striking the floor isa)0.5 mb)0.75 mc)1.0 md)1.5 mCorrect answer is option 'B'. Can you explain this answer?
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