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Let a, b ∈ R be such that the equation ax2 - 2bx + 15 = 0 has a repeated root α. If α and β are the roots of the equation x2 - 2bx + 21 = 0, then α2 + β2 is equal to
- a)37
- b)58
- c)68
- d)92
Correct answer is option 'B'. Can you explain this answer?
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Let a, b ∈R be such that the equation ax2 - 2bx + 15 = 0 has a re...
, and c be real numbers such that a ≠ 0. The quadratic equation ax^2 + bx + c = 0 has two solutions, given by the quadratic formula:
x = (-b ± √(b^2 - 4ac)) / (2a)
The discriminant, b^2 - 4ac, can be used to determine the nature of the solutions.
1. If the discriminant is positive (b^2 - 4ac > 0), the quadratic equation has two distinct real solutions.
2. If the discriminant is zero (b^2 - 4ac = 0), the quadratic equation has one real solution (a double root).
3. If the discriminant is negative (b^2 - 4ac < 0),="" the="" quadratic="" equation="" has="" two="" complex="" solutions="" (conjugate="" />
These solutions can be graphically represented as the x-intercepts of the quadratic function f(x) = ax^2 + bx + c on a coordinate plane.
x = (-b ± √(b^2 - 4ac)) / (2a)
The discriminant, b^2 - 4ac, can be used to determine the nature of the solutions.
1. If the discriminant is positive (b^2 - 4ac > 0), the quadratic equation has two distinct real solutions.
2. If the discriminant is zero (b^2 - 4ac = 0), the quadratic equation has one real solution (a double root).
3. If the discriminant is negative (b^2 - 4ac < 0),="" the="" quadratic="" equation="" has="" two="" complex="" solutions="" (conjugate="" />
These solutions can be graphically represented as the x-intercepts of the quadratic function f(x) = ax^2 + bx + c on a coordinate plane.
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Let a, b ∈R be such that the equation ax2 - 2bx + 15 = 0 has a re...
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Let a, b ∈R be such that the equation ax2 - 2bx + 15 = 0 has a repeated root α. If αand βare the roots of the equation x2 - 2bx + 21 = 0, then α2 +β2is equal toa)37b)58c)68d)92Correct answer is option 'B'. Can you explain this answer?
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Let a, b ∈R be such that the equation ax2 - 2bx + 15 = 0 has a repeated root α. If αand βare the roots of the equation x2 - 2bx + 21 = 0, then α2 +β2is equal toa)37b)58c)68d)92Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Let a, b ∈R be such that the equation ax2 - 2bx + 15 = 0 has a repeated root α. If αand βare the roots of the equation x2 - 2bx + 21 = 0, then α2 +β2is equal toa)37b)58c)68d)92Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Let a, b ∈R be such that the equation ax2 - 2bx + 15 = 0 has a repeated root α. If αand βare the roots of the equation x2 - 2bx + 21 = 0, then α2 +β2is equal toa)37b)58c)68d)92Correct answer is option 'B'. Can you explain this answer?.
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