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A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is
- a)20.12 kN/m3
- b)19.03 kN/m3
- c)21.12 kN/m3
- d)18.50 kN/m3
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
A partially-saturated soil samples has natural moisture content of 25%...
To determine the unit weight of the soil sample on full saturation, we can use the equation:
γsat = (1 + e) * γw
Where:
γsat is the unit weight of the soil sample on full saturation
e is the void ratio
γw is the unit weight of water
1. Determine the void ratio (e):
To find the void ratio, we can use the equation:
e = (ω / (1 - ω)) * (Gs / γw)
Where:
ω is the natural moisture content
Gs is the specific gravity of soil solids
γw is the unit weight of water
Given:
ω = 25%
Gs = 2.65
γw = 9.81 kN/m3
Substituting the given values into the equation, we get:
e = (0.25 / (1 - 0.25)) * (2.65 / 9.81)
e = 0.33
2. Calculate the unit weight of the soil sample on full saturation (γsat):
Using the equation mentioned earlier:
γsat = (1 + e) * γw
Substituting the values we have:
γsat = (1 + 0.33) * 9.81 kN/m3
γsat = 1.33 * 9.81 kN/m3
γsat = 13.03 kN/m3
Therefore, the unit weight of the soil sample on full saturation is 13.03 kN/m3, which corresponds to option B.
γsat = (1 + e) * γw
Where:
γsat is the unit weight of the soil sample on full saturation
e is the void ratio
γw is the unit weight of water
1. Determine the void ratio (e):
To find the void ratio, we can use the equation:
e = (ω / (1 - ω)) * (Gs / γw)
Where:
ω is the natural moisture content
Gs is the specific gravity of soil solids
γw is the unit weight of water
Given:
ω = 25%
Gs = 2.65
γw = 9.81 kN/m3
Substituting the given values into the equation, we get:
e = (0.25 / (1 - 0.25)) * (2.65 / 9.81)
e = 0.33
2. Calculate the unit weight of the soil sample on full saturation (γsat):
Using the equation mentioned earlier:
γsat = (1 + e) * γw
Substituting the values we have:
γsat = (1 + 0.33) * 9.81 kN/m3
γsat = 1.33 * 9.81 kN/m3
γsat = 13.03 kN/m3
Therefore, the unit weight of the soil sample on full saturation is 13.03 kN/m3, which corresponds to option B.
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Community Answer
A partially-saturated soil samples has natural moisture content of 25%...
w = 0.25
γT = 18.5 kN/m3
G = 2.65
γω = 9.81 kN/m3
Hence, the correct option is (B).
γT = 18.5 kN/m3
G = 2.65
γω = 9.81 kN/m3
Hence, the correct option is (B).
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A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is a)20.12 kN/m3b)19.03 kN/m3c)21.12 kN/m3d)18.50 kN/m3Correct answer is option 'B'. Can you explain this answer?
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A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is a)20.12 kN/m3b)19.03 kN/m3c)21.12 kN/m3d)18.50 kN/m3Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is a)20.12 kN/m3b)19.03 kN/m3c)21.12 kN/m3d)18.50 kN/m3Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is a)20.12 kN/m3b)19.03 kN/m3c)21.12 kN/m3d)18.50 kN/m3Correct answer is option 'B'. Can you explain this answer?.
A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is a)20.12 kN/m3b)19.03 kN/m3c)21.12 kN/m3d)18.50 kN/m3Correct answer is option 'B'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is a)20.12 kN/m3b)19.03 kN/m3c)21.12 kN/m3d)18.50 kN/m3Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A partially-saturated soil samples has natural moisture content of 25% and bulk unit weight of 18.5 kN/m3. The specific gravity of soil solids is 2.65 and unit weight of water is 9.81 kN/m3. The unit weight of soil sample on full saturation is a)20.12 kN/m3b)19.03 kN/m3c)21.12 kN/m3d)18.50 kN/m3Correct answer is option 'B'. Can you explain this answer?.
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