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The solution of the second-order differential equation   with boundary conditions y(0) = 1 and y(1) = 3 is 
  • a)
  • b)
  • c)
    e−x + (3e−1) xe−x  
  • d)
    e−x - (3e−1) xe−x  
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
The solution of the second-order differential equationwith boundary co...

y(0) = 1
y(1) = 3
(D2 + 2D+ 1) y = 0
Auxiliary equation, m2 + 2m+1 = 0
(m +1)= 0
m = ±1  
So,  CF + PI = (C1 + C2x)e−x
y(0) = 1 ⇒ C1 = 1
y(1) = 3 ⇒ C2 = 3e-1  
So,  y = [1+ (3e - 1) x]e-x
Hence, the correct option is (C).
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The solution of the second-order differential equationwith boundary conditionsy(0) = 1 and y(1) = 3 isa)b)c)e−x + (3e−1) xe−x d)e−x- (3e−1) xe−x Correct answer is option 'C'. Can you explain this answer?
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