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A 50 mL sample of industrial wastewater is taken into a silica crucible. The empty weight of the crucible is 54.352 g. The crucible with the sample is dried in a hot air oven at 104°C till a constant weight of 55.129g. Thereafter, the crucible with the dried sample is fired at 600°C for 1 h in a muffle furnace, and the weight of the crucible along with residue is determined as 54.783 g. The concentration of total volatile solids is 
  • a)
    6920 mg/L
  • b)
    8620 mg/L
  • c)
    1700 mg/L
  • d)
    15540 mg/L 
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
A 50 mL sample of industrial wastewater is taken into a silica crucibl...
Given :  
Crucible weight = 54.352 gms  
Crucible + total solids weight = 55.129 gms  
Crucible + fixed solid weight = 54.783 gms  
Volatile solids = Total solids – Fixed solid = 55.129 – 54.783 = 0.346 gms

Hence, the correct option is (A).  
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Community Answer
A 50 mL sample of industrial wastewater is taken into a silica crucibl...
°C for 1 hour. After drying, the crucible with the sample weighs 54.832 g.

To calculate the weight of the dried sample, we can subtract the weight of the empty crucible from the weight of the crucible with the sample after drying:

Weight of dried sample = Weight of crucible with sample after drying - Weight of empty crucible
Weight of dried sample = 54.832 g - 54.352 g
Weight of dried sample = 0.48 g

Therefore, the weight of the dried sample is 0.48 g.
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A 50 mL sample of industrial wastewater is taken into a silica crucible. The empty weight of the crucible is 54.352 g. The crucible with the sample is dried in a hot air oven at 104°C till a constant weight of 55.129g. Thereafter, the crucible with the dried sample is fired at 600°C for 1 h in a muffle furnace, and the weight of the crucible along with residue is determined as 54.783 g. The concentration of total volatile solids isa)6920 mg/Lb)8620 mg/Lc)1700 mg/Ld)15540 mg/LCorrect answer is option 'A'. Can you explain this answer?
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A 50 mL sample of industrial wastewater is taken into a silica crucible. The empty weight of the crucible is 54.352 g. The crucible with the sample is dried in a hot air oven at 104°C till a constant weight of 55.129g. Thereafter, the crucible with the dried sample is fired at 600°C for 1 h in a muffle furnace, and the weight of the crucible along with residue is determined as 54.783 g. The concentration of total volatile solids isa)6920 mg/Lb)8620 mg/Lc)1700 mg/Ld)15540 mg/LCorrect answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A 50 mL sample of industrial wastewater is taken into a silica crucible. The empty weight of the crucible is 54.352 g. The crucible with the sample is dried in a hot air oven at 104°C till a constant weight of 55.129g. Thereafter, the crucible with the dried sample is fired at 600°C for 1 h in a muffle furnace, and the weight of the crucible along with residue is determined as 54.783 g. The concentration of total volatile solids isa)6920 mg/Lb)8620 mg/Lc)1700 mg/Ld)15540 mg/LCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 50 mL sample of industrial wastewater is taken into a silica crucible. The empty weight of the crucible is 54.352 g. The crucible with the sample is dried in a hot air oven at 104°C till a constant weight of 55.129g. Thereafter, the crucible with the dried sample is fired at 600°C for 1 h in a muffle furnace, and the weight of the crucible along with residue is determined as 54.783 g. The concentration of total volatile solids isa)6920 mg/Lb)8620 mg/Lc)1700 mg/Ld)15540 mg/LCorrect answer is option 'A'. Can you explain this answer?.
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