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A light wave is travelling linearly in a medium of dielectric constant 4, incident on the horizontal interface separating medium with air. The angle of incidence for which the total intensity of incident wave will be reflected back into the same medium will be (Given: relative permeability of medium μr= 1)
  • a)
    10°
  • b)
    20°
  • c)
    30°
  • d)
    60°
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A light wave is travelling linearly in a medium of dielectric constant...
The total intensity of the incident wave will be reflected back into the same medium when the angle of incidence is equal to the critical angle. The critical angle can be determined using Snell's law.

Snell's law states that n1sinθ1 = n2sinθ2, where n1 and n2 are the refractive indices of the two media and θ1 and θ2 are the angles of incidence and refraction, respectively.

In this case, the incident medium is the medium with dielectric constant 4 (let's call it medium 1) and the refractive index of medium 1 is given by n1 = √(εr) = √4 = 2. The other medium is air, which has a refractive index of n2 = 1.

Let's denote the critical angle as θc. At the critical angle, the refracted angle θ2 becomes 90 degrees (sinθ2 = 1), and we can rewrite Snell's law as:

n1sinθc = n2sin90

2sinθc = 1

sinθc = 1/2

θc = sin^(-1)(1/2)

Using a calculator, we find that sin^(-1)(1/2) is approximately 30 degrees.

Therefore, the angle of incidence for which the total intensity of the incident wave will be reflected back into the same medium is approximately 30 degrees.
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Community Answer
A light wave is travelling linearly in a medium of dielectric constant...
For total internal reflection, i > θC
Taking the sine function on both sides, we get

Permeability, 

From (1), sin i > 1/2
⇒  i > 30°, i = 60°
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A light wave is travelling linearly in a medium of dielectric constant 4, incident on the horizontal interface separating medium with air. The angle of incidence for which the total intensity of incident wave will be reflected back into the same medium will be (Given: relative permeability of medium μr= 1)a)10°b)20°c)30°d)60°Correct answer is option 'D'. Can you explain this answer?
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