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The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8 m. The value of x is __________. (Nearest Integer)
(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18 J; h = 6.63 × 10-34 Js and c = 3 × 108 ms-1)
(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18 J; h = 6.63 × 10-34 Js and c = 3 × 108 ms-1)
Correct answer is '4'. Can you explain this answer?
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The longest wavelength of light that can be used for the ionisation of...
To ionize a lithium atom (Li) in its ground state, an electron needs to be completely removed from the atom. This requires a minimum energy equal to the ionization energy of lithium.
The ionization energy of lithium is 5.391 electron volts (eV), which corresponds to a wavelength of about 230 nanometers (nm).
Using the formula E = hc/λ, where E is the energy of a photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon, we can solve for the longest wavelength of light that can ionize lithium:
E = 5.391 eV = hc/λ
λ = hc/E
Plugging in the values for h and c, we get:
λ = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (5.391 eV x 1.602 x 10^-19 J/eV)
λ = 230 nm
Therefore, the longest wavelength of light that can be used for the ionization of lithium atom (Li) in its ground state is 230 nanometers.
The ionization energy of lithium is 5.391 electron volts (eV), which corresponds to a wavelength of about 230 nanometers (nm).
Using the formula E = hc/λ, where E is the energy of a photon, h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon, we can solve for the longest wavelength of light that can ionize lithium:
E = 5.391 eV = hc/λ
λ = hc/E
Plugging in the values for h and c, we get:
λ = (6.626 x 10^-34 J s) x (2.998 x 10^8 m/s) / (5.391 eV x 1.602 x 10^-19 J/eV)
λ = 230 nm
Therefore, the longest wavelength of light that can be used for the ionization of lithium atom (Li) in its ground state is 230 nanometers.
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The longest wavelength of light that can be used for the ionisation of...
Energy required for ionisation of Li Atom
=
[Assume this formula is true for LI Atom]
=
[Assume this formula is true for LI Atom]
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The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8m. The value of x is __________. (Nearest Integer)(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18J; h = 6.63 × 10-34Js and c = 3 × 108ms-1)Correct answer is '4'. Can you explain this answer?
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The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8m. The value of x is __________. (Nearest Integer)(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18J; h = 6.63 × 10-34Js and c = 3 × 108ms-1)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8m. The value of x is __________. (Nearest Integer)(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18J; h = 6.63 × 10-34Js and c = 3 × 108ms-1)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8m. The value of x is __________. (Nearest Integer)(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18J; h = 6.63 × 10-34Js and c = 3 × 108ms-1)Correct answer is '4'. Can you explain this answer?.
The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8m. The value of x is __________. (Nearest Integer)(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18J; h = 6.63 × 10-34Js and c = 3 × 108ms-1)Correct answer is '4'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8m. The value of x is __________. (Nearest Integer)(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18J; h = 6.63 × 10-34Js and c = 3 × 108ms-1)Correct answer is '4'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The longest wavelength of light that can be used for the ionisation of lithium atom (Li) in its ground state is x × 10-8m. The value of x is __________. (Nearest Integer)(Given: Energy of the electron in the first shell of the hydrogen atom is -2.2 × 10-18J; h = 6.63 × 10-34Js and c = 3 × 108ms-1)Correct answer is '4'. Can you explain this answer?.
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