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For a given chemical reaction,Concentration of C changes from 10 mmol dm-3to 20 mmol dm-3in 10 seconds. Rate of appearance of D is 1.5 times the rate of disappearance of B which is twice the rate of disappearance A. The rate of appearance of D has been experimentally determined to be 9 mmol dm-3s-1. Therefore, the rate of reaction is _________ mmol dm-3s-1. (Nearest Integer)Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about For a given chemical reaction,Concentration of C changes from 10 mmol dm-3to 20 mmol dm-3in 10 seconds. Rate of appearance of D is 1.5 times the rate of disappearance of B which is twice the rate of disappearance A. The rate of appearance of D has been experimentally determined to be 9 mmol dm-3s-1. Therefore, the rate of reaction is _________ mmol dm-3s-1. (Nearest Integer)Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for For a given chemical reaction,Concentration of C changes from 10 mmol dm-3to 20 mmol dm-3in 10 seconds. Rate of appearance of D is 1.5 times the rate of disappearance of B which is twice the rate of disappearance A. The rate of appearance of D has been experimentally determined to be 9 mmol dm-3s-1. Therefore, the rate of reaction is _________ mmol dm-3s-1. (Nearest Integer)Correct answer is '1'. Can you explain this answer?.

Solutions for For a given chemical reaction,Concentration of C changes from 10 mmol dm-3to 20 mmol dm-3in 10 seconds. Rate of appearance of D is 1.5 times the rate of disappearance of B which is twice the rate of disappearance A. The rate of appearance of D has been experimentally determined to be 9 mmol dm-3s-1. Therefore, the rate of reaction is _________ mmol dm-3s-1. (Nearest Integer)Correct answer is '1'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

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