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The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is
- a)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OH
- b)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OH
- c)(i) SOCl2 (ii) KCN (iii) CH3NH2
- d)(i) HCl (ii) CH3NH2
Correct answer is option 'A'. Can you explain this answer?
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The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents is:
(i) SOCl2
(ii) KCN
(iii) H2/Ni, Na(Hg)/C2H5OH
Let's understand the process step by step:
(i) Conversion of propan-1-ol to propanoyl chloride (propanoyl chloride is formed by the reaction of propan-1-ol with thionyl chloride, SOCl2)
- Propan-1-ol reacts with thionyl chloride (SOCl2) to form propanoyl chloride. This reaction is an example of the conversion of an alcohol to an acyl chloride. The hydroxyl group (-OH) of the alcohol is replaced by a chlorine atom (-Cl) from the thionyl chloride.
- The reaction can be represented as follows:
Propan-1-ol + SOCl2 -> Propanoyl chloride + HCl
(ii) Conversion of propanoyl chloride to nitrile (propanoyl chloride reacts with potassium cyanide, KCN to form propanonitrile)
- Propanoyl chloride reacts with potassium cyanide (KCN) to form propanonitrile. This reaction is an example of the conversion of an acyl chloride to a nitrile. The chlorine atom (-Cl) of the acyl chloride is replaced by a cyano group (-CN) from the potassium cyanide.
- The reaction can be represented as follows:
Propanoyl chloride + KCN -> Propanonitrile + KCl
(iii) Reduction of propanonitrile to n-butylamine (propanonitrile reacts with hydrogen gas in the presence of a catalyst such as nickel or sodium amalgam/ethyl alcohol to form n-butylamine)
- Propanonitrile is reduced to n-butylamine by reacting it with hydrogen gas (H2) in the presence of a catalyst such as nickel (Ni) or sodium amalgam (Na(Hg))/ethyl alcohol (C2H5OH). This reduction reaction converts the nitrile group (-CN) to an amine group (-NH2).
- The reaction can be represented as follows:
Propanonitrile + H2/Ni, Na(Hg)/C2H5OH -> n-Butylamine
Hence, the correct sequential order of reagents for the conversion of propan-1-ol to n-butylamine is (i) SOCl2, (ii) KCN, and (iii) H2/Ni, Na(Hg)/C2H5OH.
(i) SOCl2
(ii) KCN
(iii) H2/Ni, Na(Hg)/C2H5OH
Let's understand the process step by step:
(i) Conversion of propan-1-ol to propanoyl chloride (propanoyl chloride is formed by the reaction of propan-1-ol with thionyl chloride, SOCl2)
- Propan-1-ol reacts with thionyl chloride (SOCl2) to form propanoyl chloride. This reaction is an example of the conversion of an alcohol to an acyl chloride. The hydroxyl group (-OH) of the alcohol is replaced by a chlorine atom (-Cl) from the thionyl chloride.
- The reaction can be represented as follows:
Propan-1-ol + SOCl2 -> Propanoyl chloride + HCl
(ii) Conversion of propanoyl chloride to nitrile (propanoyl chloride reacts with potassium cyanide, KCN to form propanonitrile)
- Propanoyl chloride reacts with potassium cyanide (KCN) to form propanonitrile. This reaction is an example of the conversion of an acyl chloride to a nitrile. The chlorine atom (-Cl) of the acyl chloride is replaced by a cyano group (-CN) from the potassium cyanide.
- The reaction can be represented as follows:
Propanoyl chloride + KCN -> Propanonitrile + KCl
(iii) Reduction of propanonitrile to n-butylamine (propanonitrile reacts with hydrogen gas in the presence of a catalyst such as nickel or sodium amalgam/ethyl alcohol to form n-butylamine)
- Propanonitrile is reduced to n-butylamine by reacting it with hydrogen gas (H2) in the presence of a catalyst such as nickel (Ni) or sodium amalgam (Na(Hg))/ethyl alcohol (C2H5OH). This reduction reaction converts the nitrile group (-CN) to an amine group (-NH2).
- The reaction can be represented as follows:
Propanonitrile + H2/Ni, Na(Hg)/C2H5OH -> n-Butylamine
Hence, the correct sequential order of reagents for the conversion of propan-1-ol to n-butylamine is (i) SOCl2, (ii) KCN, and (iii) H2/Ni, Na(Hg)/C2H5OH.
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The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer?
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The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer?.
The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer?.
Solutions for The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
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The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer?, a detailed solution for The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The conversion of propan-1-ol to n-butylamine involves the sequential addition of reagents. The correct sequential order of reagents isa)(i) SOCl2 (ii) KCN (iii) H2/Ni, Na(Hg)/C2H5OHb)(i) HCl (ii) H2/Ni, Na(Hg)/C2H5OHc)(i) SOCl2 (ii) KCN (iii) CH3NH2d)(i) HCl (ii) CH3NH2Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
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