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A particle is moving in the xy-plane along a curve C passing through the point (3, 3). The tangent to the curve C at point P meets the x-axis at Q. If the y-axis bisects the segment PQ, then C is a parabola with
- a)length of latus rectum 3
- b)length of latus rectum 6
- c)focus (4/3 , 0)
- d)focus (0 , 3/4)
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A particle is moving in the xy-plane along a curve C passing through t...
Mid Point of PQ lies on y axis
y2 = kx
It passes through (3, 3) ⇒ k = 3
curve c ⇒ y2 = 3x
Length of L.R. = 3
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A particle is moving in the xy-plane along a curve C passing through t...
To find the correct answer, we need to analyze the given information step by step:
1. The particle is moving in the xy-plane along a curve C passing through the point (3, 3). This means that the curve C can be represented by an equation in the form y = f(x).
2. The tangent to the curve C at point P meets the x-axis at point Q. Let the coordinates of point P be (a, b). Since point P lies on the curve C, we can write the equation of the tangent at point P as y - b = f'(a)(x - a), where f'(a) represents the derivative of the function f(x) at point a.
3. The y-axis bisects the segment PQ. This means that the coordinates of point Q are (0, -2b).
4. We can find the equation of the tangent at point P by substituting the coordinates of point Q into the equation of the tangent. This gives us -2b - b = f'(a)(0 - a), which simplifies to -3b = -af'(a).
5. Since the y-axis bisects the segment PQ, the coordinates of point P are (a, b/2). Substituting these coordinates into the equation of the curve C, we get b/2 = f(a).
6. Combining the equations from steps 4 and 5, we have -3b = -af'(a) = -2af(a). Dividing both sides by -2a, we get 3b/2a = f(a).
7. The length of the latus rectum of a parabola is given by the formula 4a, where a is the coefficient of x^2 in the equation of the parabola. Comparing this with the equation in step 6, we can conclude that the length of the latus rectum is 4a = 3b/2.
8. Since the length of the latus rectum is given as 3, we can equate it with the expression 3b/2. This gives us 3 = 3b/2, which implies b = 2. Substituting this value of b into the equation in step 7, we get 4a = 3(2)/2, which simplifies to 4a = 3.
9. Therefore, the length of the latus rectum of the parabola C is 3, which is option A.
In conclusion, by using the given information and analyzing the properties of the curve C, we can determine that the correct answer is option A, which states that the length of the latus rectum is 3.
1. The particle is moving in the xy-plane along a curve C passing through the point (3, 3). This means that the curve C can be represented by an equation in the form y = f(x).
2. The tangent to the curve C at point P meets the x-axis at point Q. Let the coordinates of point P be (a, b). Since point P lies on the curve C, we can write the equation of the tangent at point P as y - b = f'(a)(x - a), where f'(a) represents the derivative of the function f(x) at point a.
3. The y-axis bisects the segment PQ. This means that the coordinates of point Q are (0, -2b).
4. We can find the equation of the tangent at point P by substituting the coordinates of point Q into the equation of the tangent. This gives us -2b - b = f'(a)(0 - a), which simplifies to -3b = -af'(a).
5. Since the y-axis bisects the segment PQ, the coordinates of point P are (a, b/2). Substituting these coordinates into the equation of the curve C, we get b/2 = f(a).
6. Combining the equations from steps 4 and 5, we have -3b = -af'(a) = -2af(a). Dividing both sides by -2a, we get 3b/2a = f(a).
7. The length of the latus rectum of a parabola is given by the formula 4a, where a is the coefficient of x^2 in the equation of the parabola. Comparing this with the equation in step 6, we can conclude that the length of the latus rectum is 4a = 3b/2.
8. Since the length of the latus rectum is given as 3, we can equate it with the expression 3b/2. This gives us 3 = 3b/2, which implies b = 2. Substituting this value of b into the equation in step 7, we get 4a = 3(2)/2, which simplifies to 4a = 3.
9. Therefore, the length of the latus rectum of the parabola C is 3, which is option A.
In conclusion, by using the given information and analyzing the properties of the curve C, we can determine that the correct answer is option A, which states that the length of the latus rectum is 3.
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A particle is moving in the xy-plane along a curve C passing through the point (3, 3). The tangent to the curve C at point P meets the x-axis at Q. If the y-axis bisects the segment PQ, then C is a parabola witha)length of latus rectum 3b)length of latus rectum 6c)focus (4/3 , 0)d)focus (0 , 3/4)Correct answer is option 'A'. Can you explain this answer?
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