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A pressure measurement device fitted on the surface of a submarine located at a depth of H below the surface of an ocean, reads an absolute pressure of 4.2MPa . The density of sea water is 1050 kg/m3 , the atmospheric pressure is 101 kPa, and the acceleration due to gravity is 9.8 m/s2 . The depth H is __________ m.
Correct answer is '398.347'. Can you explain this answer?
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A pressure measurement device fitted on the surface of a submarine loc...
Given:
- Absolute pressure on the surface of the submarine (P) = 4.2 MPa
- Density of sea water (ρ) = 1050 kg/m^3
- Atmospheric pressure (Patm) = 101 kPa
- Acceleration due to gravity (g) = 9.8 m/s^2
Formula:
- Absolute pressure (P) = Pressure due to depth (Pdepth) + Atmospheric pressure (Patm)
- Pressure due to depth (Pdepth) = ρ * g * H
Calculation:
Using the given formula, we can rewrite the equation as:
P = ρ * g * H + Patm
Let's convert the units to SI:
- P = 4.2 * 10^6 Pa
- Patm = 101 * 10^3 Pa
Substituting the values in the equation:
4.2 * 10^6 = 1050 * 9.8 * H + 101 * 10^3
Simplifying the equation:
4.2 * 10^6 - 101 * 10^3 = 1050 * 9.8 * H
Calculating the left side of the equation:
4.2 * 10^6 - 101 * 10^3 = 399 * 10^3
Substituting the value back into the equation:
399 * 10^3 = 1050 * 9.8 * H
Dividing both sides by (1050 * 9.8):
H = 399 * 10^3 / (1050 * 9.8)
Calculating the right side of the equation:
H = 398.347 m
Therefore, the depth H below the surface of the ocean is 398.347 m.
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Community Answer
A pressure measurement device fitted on the surface of a submarine loc...
Given : Patm = 101 kPa
P = 4.2 MPa = 4.2×106 Pa
ρsea = 1050 kg / m3
P = Patm + ρsea gH
4.2 × 106= 101× 103 + 1050 × 9.8 × H
H = 398.347 m
P = 4.2 MPa = 4.2×106 Pa
ρsea = 1050 kg / m3
P = Patm + ρsea gH
4.2 × 106= 101× 103 + 1050 × 9.8 × H
H = 398.347 m
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A pressure measurement device fitted on the surface of a submarine located at a depth of H below the surface of an ocean, reads an absolute pressure of 4.2MPa . The density of sea water is 1050 kg/m3 , the atmospheric pressure is 101 kPa, and the acceleration due to gravity is 9.8 m/s2 . The depth H is __________ m.Correct answer is '398.347'. Can you explain this answer?
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A pressure measurement device fitted on the surface of a submarine located at a depth of H below the surface of an ocean, reads an absolute pressure of 4.2MPa . The density of sea water is 1050 kg/m3 , the atmospheric pressure is 101 kPa, and the acceleration due to gravity is 9.8 m/s2 . The depth H is __________ m.Correct answer is '398.347'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A pressure measurement device fitted on the surface of a submarine located at a depth of H below the surface of an ocean, reads an absolute pressure of 4.2MPa . The density of sea water is 1050 kg/m3 , the atmospheric pressure is 101 kPa, and the acceleration due to gravity is 9.8 m/s2 . The depth H is __________ m.Correct answer is '398.347'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A pressure measurement device fitted on the surface of a submarine located at a depth of H below the surface of an ocean, reads an absolute pressure of 4.2MPa . The density of sea water is 1050 kg/m3 , the atmospheric pressure is 101 kPa, and the acceleration due to gravity is 9.8 m/s2 . The depth H is __________ m.Correct answer is '398.347'. Can you explain this answer?.
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