All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  Spin-only magnetic moment of an octahedral co... Start Learning for Free
Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. is
  • a)
    4.89
  • b)
    0
  • c)
    2.82
  • d)
    3.46
Correct answer is option 'B'. Can you explain this answer?
Clear all your JEE doubts with EduRev
Most Upvoted Answer
Spin-only magnetic moment of an octahedral complex of Fe2+ in the pres...
Free Test
FREE
Start Free Test
Start Free Test
Community Answer
Spin-only magnetic moment of an octahedral complex of Fe2+ in the pres...
Understanding the Spin-Only Magnetic Moment
The spin-only magnetic moment is an important concept in coordination chemistry, particularly for transition metal complexes. It is calculated using the formula:
μ = √(n(n + 2)),
where n = number of unpaired electrons.
Fe2+ in an Octahedral Complex
- Iron (Fe) has an atomic number of 26, and in its +2 oxidation state, Fe2+ has the electronic configuration of [Ar] 3d^6.
- In an octahedral field, the 3d orbitals split into two sets: t2g (lower energy) and eg (higher energy).
Strong Field Ligands
- Strong field ligands, such as CN- or CO, cause a significant splitting of the d-orbitals and promote pairing of electrons.
- In the case of Fe2+ with a strong field ligand, the six d-electrons (3d^6) will fill the t2g orbitals first, resulting in:
- t2g: 6 electrons (3 pairs)
- eg: 0 electrons
This leads to no unpaired electrons.
Calculating the Spin-Only Magnetic Moment
- Since all the electrons are paired in the t2g orbitals, n (the number of unpaired electrons) is 0.
- Substituting n = 0 into the formula for magnetic moment:
μ = √(0(0 + 2)) = 0
Conclusion
Thus, the spin-only magnetic moment of the octahedral complex of Fe2+ in the presence of a strong field ligand is 0 B.M. Therefore, the correct answer is option 'B'.
Explore Courses for JEE exam

Similar JEE Doubts

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

Top Courses for JEEView all

Top Courses for JEE

Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer?
Question Description
Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer?.
Solutions for Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer?, a detailed solution for Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Spin-only magnetic moment of an octahedral complex of Fe2+ in the presence of a strong field ligand in B.M. isa)4.89b)0c)2.82d)3.46Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
SaveJoin the Discussion on the App for FREE
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup