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The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)
Correct answer is '1'. Can you explain this answer?
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The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg,...
°C are 60 mmHg and 90 mmHg, respectively. If a mixture of A and B with mole fraction of A is 0.4 is prepared, what is the total vapor pressure of the mixture at 25°C?
To find the total vapor pressure of the mixture, we can use Raoult's law, which states that the vapor pressure of a mixture is equal to the sum of the partial pressures of the components in the mixture, each multiplied by its mole fraction:
P_total = P_A * x_A + P_B * x_B
where P_A and P_B are the vapor pressures of A and B, respectively, and x_A and x_B are their mole fractions in the mixture.
Substituting the given values, we get:
P_total = 60 mmHg * 0.4 + 90 mmHg * 0.6
P_total = 24 + 54
P_total = 78 mmHg
Therefore, the total vapor pressure of the mixture at 25°C is 78 mmHg.
To find the total vapor pressure of the mixture, we can use Raoult's law, which states that the vapor pressure of a mixture is equal to the sum of the partial pressures of the components in the mixture, each multiplied by its mole fraction:
P_total = P_A * x_A + P_B * x_B
where P_A and P_B are the vapor pressures of A and B, respectively, and x_A and x_B are their mole fractions in the mixture.
Substituting the given values, we get:
P_total = 60 mmHg * 0.4 + 90 mmHg * 0.6
P_total = 24 + 54
P_total = 78 mmHg
Therefore, the total vapor pressure of the mixture at 25°C is 78 mmHg.
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The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg,...
xA = 0.6
PT = xAPAo + xBPBo
= 0.6 × 90 + 0.4 × 15
= 54 + 6 = 60
xAPAo = yAPT
0.6 × 90 = yA(60)
yA = 0.9
yB = 0.1 = 1 × 10-1
∴ x = 1
PT = xAPAo + xBPBo
= 0.6 × 90 + 0.4 × 15
= 54 + 6 = 60
xAPAo = yAPT
0.6 × 90 = yA(60)
yA = 0.9
yB = 0.1 = 1 × 10-1
∴ x = 1
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The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)Correct answer is '1'. Can you explain this answer?
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The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)Correct answer is '1'. Can you explain this answer?.
The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)Correct answer is '1'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)Correct answer is '1'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The vapour pressures of A and B at 25°C are 90 mm Hg and 15 mm Hg, respectively. If A and B are mixed such that the mole fraction of A in the mixture is 0.6, then the mole fraction of B in the vapour phase is x × 10-1. The value of x is _________. (Nearest integer)Correct answer is '1'. Can you explain this answer?.
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