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A carrier wave VC(t) = 160 sin(2 π × 106 t) volts is made to vary between Vmax = 200 V and Vmin = 120 V by a message signal Vm(t) = Am sin(2 π × 103t) volts. The peak voltage Am of the modulating signal is __________.
    Correct answer is '40'. Can you explain this answer?
    Most Upvoted Answer
    A carrier wave VC(t) = 160 sin(2 π × 106 t) volts is made to ...
    Amax = Am + AC
    ⇒ vmax = Vm + VC
    200 = Vm + 160
    Vm = 40
    ∴  Peak voltage, Am = 40
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    Community Answer
    A carrier wave VC(t) = 160 sin(2 π × 106 t) volts is made to ...
    A carrier wave Vc(t) = 160 sin(2π fct), where Vc(t) is the carrier wave voltage, f is the frequency of the carrier wave, and ct is the carrier wave phase.

    The equation for the carrier wave can be written as:

    Vc(t) = 160 sin(2π fct)

    In this equation, 160 is the amplitude of the carrier wave. The sine function represents the variation of the carrier wave voltage over time. The argument of the sine function, 2π fct, determines the frequency and phase of the carrier wave.

    Frequency (f) is the number of cycles of the carrier wave that occur per second. It is measured in Hertz (Hz). The phase (ct) represents the initial angle of the carrier wave at time t=0. It is measured in radians.

    To fully describe the carrier wave, you need to know the values of the amplitude, frequency, and phase.
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    A carrier wave VC(t) = 160 sin(2 π × 106 t) volts is made to vary between Vmax = 200 V and Vmin = 120 V by a message signal Vm(t) = Am sin(2 π × 103t) volts. The peak voltage Am of the modulating signal is __________.Correct answer is '40'. Can you explain this answer?
    Question Description
    A carrier wave VC(t) = 160 sin(2 π × 106 t) volts is made to vary between Vmax = 200 V and Vmin = 120 V by a message signal Vm(t) = Am sin(2 π × 103t) volts. The peak voltage Am of the modulating signal is __________.Correct answer is '40'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A carrier wave VC(t) = 160 sin(2 π × 106 t) volts is made to vary between Vmax = 200 V and Vmin = 120 V by a message signal Vm(t) = Am sin(2 π × 103t) volts. The peak voltage Am of the modulating signal is __________.Correct answer is '40'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A carrier wave VC(t) = 160 sin(2 π × 106 t) volts is made to vary between Vmax = 200 V and Vmin = 120 V by a message signal Vm(t) = Am sin(2 π × 103t) volts. The peak voltage Am of the modulating signal is __________.Correct answer is '40'. Can you explain this answer?.
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