All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  The spin-only magnetic moment value for the c... Start Learning for Free
The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27]
(Nearest integer).
    Correct answer is '2'. Can you explain this answer?
    Clear all your JEE doubts with EduRev
    Most Upvoted Answer
    The spin-only magnetic moment value for the complex [Co(CN6)]4- is ___...
    [Co(CN)6]4-
    x + 6 × (-1) = -4
    x = +2
    Co2+: [Ar] 3d7
    CN- is a strong field ligand which can pair electrons of central atom.

    It has one unpaired electron (n) in 4d-subshell.
    So, spin-only magnetic moment (μ) = BM, where n = number of unpaired electrons
    μ = √3 BM
    μ = 1.73 BM
    μ = 2 BM
    Free Test
    FREE
    Start Free Test
    		Start Free Test
    Community Answer
    The spin-only magnetic moment value for the complex [Co(CN6)]4- is ___...
    The spin-only magnetic moment value for the complex [Co(CN6)]4- is 2 BM.

    Explanation:
    The spin-only magnetic moment can be calculated using the formula:

    μs = √(n(n+2)) BM

    where μs is the spin-only magnetic moment, n is the number of unpaired electrons, and BM is the Bohr magneton.

    To determine the number of unpaired electrons in the complex [Co(CN6)]4-, we need to consider the electronic configuration of cobalt (Co).

    The atomic number of cobalt is 27, which means it has 27 electrons. The electronic configuration of Co is [Ar] 3d7 4s2.

    In the complex [Co(CN6)]4-, the cyanide ligands (CN-) are strong-field ligands that cause pairing of electrons in the d orbitals. This leads to the formation of low-spin complexes.

    In a low-spin complex, the electrons fill the lower energy orbitals first before pairing. Based on this, the electronic configuration of [Co(CN6)]4- can be written as [Ar] 3d6.

    Calculating the number of unpaired electrons:
    The electronic configuration [Ar] 3d6 indicates that there are 6 electrons in the d orbitals. Since each orbital can accommodate a maximum of 2 electrons, there are 3 pairs of electrons, resulting in 3 unpaired electrons.

    Calculating the spin-only magnetic moment:
    Using the formula μs = √(n(n+2)) BM, where n = 3 (number of unpaired electrons), we can calculate the spin-only magnetic moment.

    μs = √(3(3+2)) BM
    μs = √(3(5)) BM
    μs = √(15) BM
    μs ≈ 3.87 BM

    Rounding off the value to the nearest integer, the spin-only magnetic moment for [Co(CN6)]4- is 4 BM.

    However, the correct answer given is 2 BM. This suggests that there is an error in the question or the answer provided. The correct answer should be 4 BM based on the given information.
    Explore Courses for JEE exam

    Similar JEE Doubts

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    The orbital and spin angular momentum of the atom influence its magnetic structure and these properties are most directly studied by placing the atom in a magnetic field. Also, a magnetic field can affect the wavelengths of the emitted photons.The angular momentum vector associated with an atomic state can take up only certain specified directions in space. This concept of space quantization was shown by Otto Stern and Walthor Gerlach in their experiment.In the experiment, silver is vapourized in an electric oven and silver atoms spray into the evacuated apparatus through a small hole in the oven wall. The atoms which are electrically neutral but have a magnetic moment, are formed into a narrow beam as they pass through a slit in a screen. The beam, thus collimated, then passes between the poles of an electromagnet and finally, deposits its silver atoms on a glass plate that serves as a detector. The pole faces of the magnet are shaped to make the magnetic field as nonuniform as possible.In a non-uniform magnetic field, there is a net force on a magnetic dipole. Its magnitude and direction depends on the orientation of the dipole. Thus the silver atoms in the beam are deflected up or down, depending on the orientation of their magnetic dipole moments with respect to the z–direction.The potential energy of a magnetic dipole in a magnetic field where is magnetic dipole moment of the atom. From symmetry, the magnetic field at the beam position has no x or y components i.e.The net force Fz on the dipole isThus, the net force depends, not on the magnitude of the field itself, but on its spatial derivative or gradient.The ResultsIf space quantization did not exist, then could take on any value from + to –, the result would be a spreading out of the beam when the magnet was turned ON. However, the beam was split cleanly into two subbeams, each subbeam corresponding to one of the two permitted orientations of the magnetic moment ofthe silver atom, as shown.In a silver atom, all the spin and orbital magnetic moments of the electrons cancel, except for those of the atoms single valance electron. For this electron the orbital magnetic moment is zero because orbital angular momentum is zero (because for electrons of s–orbit, L = 0), leaving only the spin magnetic moment. This can take up only two orientations in a magnetic field, corresponding to ms = +1/2 and ms = – 1/2. Hence there are two subbeams – and not some other number.Q.A hydrogen atom in ground state passes through a magnetic field that has a gradient of 16mT/m in the vertical direction. If vertical component magnetic moment of the atom is 9.3 × 10–24 J/T, then force on it due to the magnetic moment of the electron is

    Top Courses for JEEView all

    Top Courses for JEE

    The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer?
    Question Description
    The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer?.
    Solutions for The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
    Here you can find the meaning of The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer?, a detailed solution for The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer? has been provided alongside types of The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The spin-only magnetic moment value for the complex [Co(CN6)]4- is ______________ BM. [At. No. of Co = 27](Nearest integer).Correct answer is '2'. Can you explain this answer? tests, examples and also practice JEE tests.
    Explore Courses for JEE exam

    Top Courses for JEE

    Explore Courses
    SaveJoin the Discussion on the App for FREE
    Signup for Free!
    Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
    10M+ students study on EduRev
    Get App
    © EduRev
    Education Revolution
    Signup to see your scores go up within 7 days!
    Access 1000+ FREE Docs, Videos and Tests
    Takes less than 10 seconds to signup