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A reading of 120 is obtained when standard inductor is connected in the circuit of a Q-meter and the variable capacitor is adjusted to value of 300 pF. A lossless capacitor of unknown value Cx is then connected in parallel with the variable capacitor and the same reading is obtained when the variable capacitor is readjusted to a value of 200 pF. The value of Cx in pF is (Answer up to the nearest integer)
    Correct answer is '100'. Can you explain this answer?
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    A reading of 120 is obtained when standard inductor is connected in t...
    Given information:
    - Reading obtained when standard inductor is connected: 120
    - Capacitance when variable capacitor is adjusted: 300 pF
    - Reading obtained when unknown capacitor is connected in parallel: 120
    - Capacitance when variable capacitor is readjusted: 200 pF

    Explanation:

    Step 1: Understanding Q-meter:
    A Q-meter is an instrument used to measure the quality factor (Q-factor) of a circuit component, such as an inductor or a capacitor. It works based on the principle of resonance.

    Step 2: Initial reading with standard inductor:
    When the standard inductor is connected to the Q-meter circuit, a reading of 120 is obtained. This means that the circuit is resonating at a certain frequency determined by the inductance and the capacitance.

    Step 3: Adjusting variable capacitor to 300 pF:
    To achieve resonance, the variable capacitor is adjusted to a value of 300 pF. This means that the total capacitance in the circuit, including the standard inductor and the variable capacitor, is equivalent to 300 pF.

    Step 4: Adding unknown capacitor in parallel:
    Now, an unknown capacitor (Cx) is connected in parallel with the variable capacitor. The resonance condition is still maintained, as the reading obtained is still 120. This implies that the total capacitance in the circuit, including the standard inductor, the variable capacitor, and the unknown capacitor, is still equivalent to 300 pF.

    Step 5: Adjusting variable capacitor to 200 pF:
    To compensate for the additional capacitance introduced by the unknown capacitor, the variable capacitor needs to be readjusted. It is now set to a value of 200 pF.

    Step 6: Determining the value of unknown capacitor:
    Since the resonance condition is still satisfied (reading remains at 120), the total capacitance in the circuit is still equivalent to 300 pF. Therefore, the unknown capacitor (Cx) must have a capacitance value equal to the difference between the initial capacitance (300 pF) and the readjusted capacitance (200 pF).

    Cx = 300 pF - 200 pF
    Cx = 100 pF

    Therefore, the value of the unknown capacitor (Cx) is 100 pF.
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    A reading of 120 is obtained when standard inductor is connected in the circuit of a Q-meter and the variable capacitor is adjusted to value of 300 pF. A lossless capacitor of unknown value Cx is then connected in parallel with the variable capacitor and the same reading is obtained when the variable capacitor is readjusted to a value of 200 pF. The value of Cx in pF is (Answer up to the nearest integer)Correct answer is '100'. Can you explain this answer?
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    A reading of 120 is obtained when standard inductor is connected in the circuit of a Q-meter and the variable capacitor is adjusted to value of 300 pF. A lossless capacitor of unknown value Cx is then connected in parallel with the variable capacitor and the same reading is obtained when the variable capacitor is readjusted to a value of 200 pF. The value of Cx in pF is (Answer up to the nearest integer)Correct answer is '100'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A reading of 120 is obtained when standard inductor is connected in the circuit of a Q-meter and the variable capacitor is adjusted to value of 300 pF. A lossless capacitor of unknown value Cx is then connected in parallel with the variable capacitor and the same reading is obtained when the variable capacitor is readjusted to a value of 200 pF. The value of Cx in pF is (Answer up to the nearest integer)Correct answer is '100'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A reading of 120 is obtained when standard inductor is connected in the circuit of a Q-meter and the variable capacitor is adjusted to value of 300 pF. A lossless capacitor of unknown value Cx is then connected in parallel with the variable capacitor and the same reading is obtained when the variable capacitor is readjusted to a value of 200 pF. The value of Cx in pF is (Answer up to the nearest integer)Correct answer is '100'. Can you explain this answer?.
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