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Consider steady state, one-dimensional heat conduction in an infinite slab of thickness 2L (L = 1 m) as shown in the figure. The conductivity (k) of the material varies with temperature as k = C��, where �� is the temperature in K, and C is a constant equal to 2 W∙m-1∙K-2. There is a uniform heat generation of 1280 kW/m3 in the slab. If both faces of the slab are maintained at 600 K, then the temperature at x = 0 is ________ K (in integer).
    Correct answer is between '990,1010'. Can you explain this answer?
    Most Upvoted Answer
    Consider steady state, one-dimensional heat conduction in an infinite ...
    Given data

    Thickness of slab 2 L (L = 1 m)
    k = CT ,
    Where
    C = 2 Wm-1 K-2
    Uniform heat generation (q) = 1280 kW / m3
    Temperature of the slab (T ) = 600 K
    Steady state, one dimensional heat conduction 

    On integrating 

    On integrating,

    Boundary condition: At x = L = 1 m ⇒ T = 600 K
    Put the value in equations (i)

    By equations (ii) and (iii) we get,
    C1 = 0
    C2 = 106
    By so equations (i) we get

    Hence, the temperature at  = 0 is 1000 K.
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    Consider steady state, one-dimensional heat conduction in an infinite slab of thickness 2L (L = 1 m) as shown in the figure. The conductivity (k) of the material varies with temperature as k = C��, where �� is the temperature in K, and C is a constant equal to 2 Wm-1K-2. There is a uniform heat generation of 1280kW/m3 in the slab. If both faces of the slab are maintained at 600 K, then the temperature at x = 0 is ________ K (in integer).Correct answer is between '990,1010'. Can you explain this answer?
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    Consider steady state, one-dimensional heat conduction in an infinite slab of thickness 2L (L = 1 m) as shown in the figure. The conductivity (k) of the material varies with temperature as k = C��, where �� is the temperature in K, and C is a constant equal to 2 Wm-1K-2. There is a uniform heat generation of 1280kW/m3 in the slab. If both faces of the slab are maintained at 600 K, then the temperature at x = 0 is ________ K (in integer).Correct answer is between '990,1010'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about Consider steady state, one-dimensional heat conduction in an infinite slab of thickness 2L (L = 1 m) as shown in the figure. The conductivity (k) of the material varies with temperature as k = C��, where �� is the temperature in K, and C is a constant equal to 2 Wm-1K-2. There is a uniform heat generation of 1280kW/m3 in the slab. If both faces of the slab are maintained at 600 K, then the temperature at x = 0 is ________ K (in integer).Correct answer is between '990,1010'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider steady state, one-dimensional heat conduction in an infinite slab of thickness 2L (L = 1 m) as shown in the figure. The conductivity (k) of the material varies with temperature as k = C��, where �� is the temperature in K, and C is a constant equal to 2 Wm-1K-2. There is a uniform heat generation of 1280kW/m3 in the slab. If both faces of the slab are maintained at 600 K, then the temperature at x = 0 is ________ K (in integer).Correct answer is between '990,1010'. Can you explain this answer?.
    Solutions for Consider steady state, one-dimensional heat conduction in an infinite slab of thickness 2L (L = 1 m) as shown in the figure. The conductivity (k) of the material varies with temperature as k = C��, where �� is the temperature in K, and C is a constant equal to 2 Wm-1K-2. There is a uniform heat generation of 1280kW/m3 in the slab. If both faces of the slab are maintained at 600 K, then the temperature at x = 0 is ________ K (in integer).Correct answer is between '990,1010'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering. Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
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