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In Fe - Fe3C phase diagram, the eutectoid composition is 0.8 weight % of carbon at 7250 C. The maximum solubility of carbon in a- ferrite phase is 0.025 weight % of carbon. A steel sample, having no other alloying element except 0.5 weight % of carbon, is slowly cooled from 10000C to room temperature. The fraction of pro-eutectoid α- ferrite in the above steel sample at room temperature is
  • a)
    0.387
  • b)
    0.864
  • c)
    0.475
  • d)
    0.775
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
In Fe - Fe3C phase diagram, the eutectoid composition is 0.8 weight % ...
Given data
The eutectoid composition at 7250C = 0.8% carbon
α- Ferrite phase = 0.025% Carbon

Fraction of pro – eutectoid 

mα =  0.387
Hence the correct option is (A).
Free Test
Community Answer
In Fe - Fe3C phase diagram, the eutectoid composition is 0.8 weight % ...
Ferrite in the final microstructure can be determined using lever rule.

First, we need to determine the composition of the pro-eutectoid ferrite phase. Since the maximum solubility of carbon in α-ferrite phase is 0.025 weight %, any carbon content above this value will form the pro-eutectoid ferrite phase.

In this case, the carbon content in the steel sample is 0.5 weight %, which is higher than the maximum solubility. Therefore, all the excess carbon will form the pro-eutectoid ferrite phase.

Fraction of pro-eutectoid ferrite = (carbon content - maximum solubility) / (eutectoid composition - maximum solubility)
= (0.5 - 0.025) / (0.8 - 0.025)
= 0.475 / 0.775
= 0.6135 or 61.35%

Therefore, the fraction of pro-eutectoid ferrite in the final microstructure is 61.35%.
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In Fe - Fe3C phase diagram, the eutectoid composition is 0.8 weight % of carbon at 7250 C. The maximum solubility of carbon in a- ferrite phase is 0.025 weight % of carbon. A steel sample, having no other alloying element except 0.5 weight % of carbon, is slowly cooled from 10000C to room temperature. The fraction of pro-eutectoid α- ferrite in the above steel sample at room temperature isa)0.387b)0.864c)0.475d)0.775Correct answer is option 'A'. Can you explain this answer?
Question Description
In Fe - Fe3C phase diagram, the eutectoid composition is 0.8 weight % of carbon at 7250 C. The maximum solubility of carbon in a- ferrite phase is 0.025 weight % of carbon. A steel sample, having no other alloying element except 0.5 weight % of carbon, is slowly cooled from 10000C to room temperature. The fraction of pro-eutectoid α- ferrite in the above steel sample at room temperature isa)0.387b)0.864c)0.475d)0.775Correct answer is option 'A'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about In Fe - Fe3C phase diagram, the eutectoid composition is 0.8 weight % of carbon at 7250 C. The maximum solubility of carbon in a- ferrite phase is 0.025 weight % of carbon. A steel sample, having no other alloying element except 0.5 weight % of carbon, is slowly cooled from 10000C to room temperature. The fraction of pro-eutectoid α- ferrite in the above steel sample at room temperature isa)0.387b)0.864c)0.475d)0.775Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In Fe - Fe3C phase diagram, the eutectoid composition is 0.8 weight % of carbon at 7250 C. The maximum solubility of carbon in a- ferrite phase is 0.025 weight % of carbon. A steel sample, having no other alloying element except 0.5 weight % of carbon, is slowly cooled from 10000C to room temperature. The fraction of pro-eutectoid α- ferrite in the above steel sample at room temperature isa)0.387b)0.864c)0.475d)0.775Correct answer is option 'A'. Can you explain this answer?.
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