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There are 200 tracks on a disc platter and the pending requests have come in the order - 36, 69, 167, 76, 42, 51, 126, 12 and 199. Assume the arm is located at the 100 track and moving towards track 199. If sequence of disc access is 126, 167, 199, 12, 36, 42, 51, 69 and 76 then which disc access scheduling policy is used?
  • a)
    Elevator
  • b)
    Shortest seek-time first
  • c)
    C-SCAN
  • d)
    First Come First Served
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
There are 200 tracks on a disc platter and the pending requests have c...
The disc access scheduling policy used is C-SCAN.

Explanation:
The C-SCAN (Circular SCAN) algorithm is a disk scheduling algorithm that works by moving the disk arm only in one direction and servicing the requests in a circular manner. When the arm reaches the end of the disk, it wraps around to the beginning and continues servicing requests in the same direction.

Given that the arm is initially located at track 100 and moving towards track 199, let's analyze the sequence of disc access to determine the scheduling policy used:

1. 126: The arm moves from track 100 towards track 199, passing through tracks 126 and 167, and finally reaches track 199.

2. 167: Since the arm is already at track 199, it does not need to move. The request is serviced.

3. 199: Same as the previous step, the arm does not need to move and the request is serviced.

4. 12: The arm has reached the end of the disk and wraps around to the beginning. It moves from track 0 to track 12 to service the request.

5. 36: The arm continues moving in the same direction from track 12 to track 36.

6. 42: The arm moves from track 36 to track 42.

7. 51: The arm moves from track 42 to track 51.

8. 69: The arm moves from track 51 to track 69.

9. 76: The arm moves from track 69 to track 76.

Conclusion:
As we can see, the sequence of disc access follows the circular pattern of the C-SCAN algorithm. The arm moves in one direction, servicing the requests in a circular manner, and wraps around to the beginning when it reaches the end of the disk. Therefore, the disc access scheduling policy used is C-SCAN.
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Community Answer
There are 200 tracks on a disc platter and the pending requests have c...
The algorithm looks similar to C- Scan.
Option (C) is correct.
 
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There are 200 tracks on a disc platter and the pending requests have come in the order - 36, 69, 167, 76, 42, 51, 126, 12 and 199. Assume the arm is located at the 100 track and moving towards track 199. If sequence of disc access is 126, 167, 199, 12, 36, 42, 51, 69 and 76 then which disc access scheduling policy is used?a)Elevatorb)Shortest seek-time firstc)C-SCANd)First Come First ServedCorrect answer is option 'C'. Can you explain this answer?
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There are 200 tracks on a disc platter and the pending requests have come in the order - 36, 69, 167, 76, 42, 51, 126, 12 and 199. Assume the arm is located at the 100 track and moving towards track 199. If sequence of disc access is 126, 167, 199, 12, 36, 42, 51, 69 and 76 then which disc access scheduling policy is used?a)Elevatorb)Shortest seek-time firstc)C-SCANd)First Come First ServedCorrect answer is option 'C'. Can you explain this answer? for Computer Science Engineering (CSE) 2025 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about There are 200 tracks on a disc platter and the pending requests have come in the order - 36, 69, 167, 76, 42, 51, 126, 12 and 199. Assume the arm is located at the 100 track and moving towards track 199. If sequence of disc access is 126, 167, 199, 12, 36, 42, 51, 69 and 76 then which disc access scheduling policy is used?a)Elevatorb)Shortest seek-time firstc)C-SCANd)First Come First ServedCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for There are 200 tracks on a disc platter and the pending requests have come in the order - 36, 69, 167, 76, 42, 51, 126, 12 and 199. Assume the arm is located at the 100 track and moving towards track 199. If sequence of disc access is 126, 167, 199, 12, 36, 42, 51, 69 and 76 then which disc access scheduling policy is used?a)Elevatorb)Shortest seek-time firstc)C-SCANd)First Come First ServedCorrect answer is option 'C'. Can you explain this answer?.
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