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A 1 mm thick cylindrical tube, 100 mm in diameter, is orthogonally turned such that the entire wall thickness of the tube is cut in a single pass. The axial feed of the tool is 1 m/minute and the specific cutting energy (u) of the tube material is 6 J/mm3. Neglect contribution of feed force towards power. The power required to carry out this operation is ________ kW (round off to one decimal place).

Correct answer is '31.4'. Can you explain this answer?
Most Upvoted Answer
A 1 mm thick cylindrical tube, 100 mm in diameter, is orthogonally tur...
Given data:
Thickness of the tube (t) = 1 mm
Diameter of the tube (D) = 100 mm
Axial feed of the tool (f) = 1 m/minute
Specific cutting energy (u) = 6 J/mm³

Calculating the volume of material to be removed:
The volume of material to be removed in a single pass can be calculated using the following equation:
V = π/4 * (D² - (D - 2t)²)

Substituting the given values:
V = π/4 * (100² - (100 - 2 * 1)²)
V = 7853.98 mm³

Calculating the time taken to remove the material:
The time taken to remove the material can be calculated using the following equation:
t = V / (f * t)

Substituting the given values:
t = 7853.98 mm³ / (1 m/minute * 1 mm)
t = 7853.98 minutes

Calculating the energy required:
The energy required can be calculated using the following equation:
E = V * u

Substituting the given values:
E = 7853.98 mm³ * 6 J/mm³
E = 47123.88 J

Calculating the power required:
Power (P) is given by the equation:
P = E / t

Substituting the calculated values:
P = 47123.88 J / 7853.98 minutes
P = 5.9984 J/minute

Converting the power from J/minute to kW:
P = 5.9984 J/minute * (1 kW / 60000 J/minute)
P = 0.0000999733 kW

Rounding off to one decimal place:
P ≈ 0.1 kW

The correct answer is 0.1 kW, not 31.4159 kW. Please double-check the given answer.
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Community Answer
A 1 mm thick cylindrical tube, 100 mm in diameter, is orthogonally tur...
Given :
Thickness (t) = 1 mm
Diameter (D) = 100 mm
Axial feed (F) = fN = 1 n/min = 1000/60 mm/sec
Specific cutting energy (G ) = 6 J/mm3

For cylindrical tube,
Area of cut ( A) = πDt
Now, 
Specific cutting energy = Power / Material removal rate

Power required, P = 31415.9 W
P = 31.4159 kW
Hence, the correct answer is 31.4159
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A 1 mm thick cylindrical tube, 100 mm in diameter, is orthogonally turned such that the entire wall thickness of the tube is cut in a single pass. The axial feed of the tool is 1 m/minute and the specific cutting energy (u) of the tube material is 6 J/mm3. Neglect contribution of feed force towards power. The power required to carry out this operation is ________ kW (round off to one decimal place).Correct answer is '31.4'. Can you explain this answer?
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