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The standard heat of formation (
) of ethane (in kJ/mol), if the heat of combustion of ethane, hydrogen and graphite is -1560, -393.5 and -286 kJ/mol, respectively, is ______.
) of ethane (in kJ/mol), if the heat of combustion of ethane, hydrogen and graphite is -1560, -393.5 and -286 kJ/mol, respectively, is ______.Correct answer is '-192.5'. Can you explain this answer?
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The standard heat of formation () of ethane (in kJ/mol), if the heat o...
(1) C + O2 → CO2, 
= -286 kJ/mol
(2) H2 + O2 → H2O,
= -393.5 kJ/mol
(3) C2H6 + O2 → 2CO2 + 3H2O,
= -1560 kJ/mol
Calculation:
2 × (1) + 3 × (2) - (3)
2C + 3H2 C2H6
(C2H6) = 2(-286) + 3(-393.5) + 1560 = -192.5 kJ/mol
= -286 kJ/mol(2) H2 + O2 → H2O,
= -393.5 kJ/mol(3) C2H6 + O2 → 2CO2 + 3H2O,
= -1560 kJ/molCalculation:
2 × (1) + 3 × (2) - (3)
2C + 3H2 C2H6
(C2H6) = 2(-286) + 3(-393.5) + 1560 = -192.5 kJ/molAttention JEE Students!
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The standard heat of formation () of ethane (in kJ/mol), if the heat of combustion of ethane, hydrogen and graphite is -1560, -393.5 and -286 kJ/mol, respectively, is ______.Correct answer is '-192.5'. Can you explain this answer?
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The standard heat of formation () of ethane (in kJ/mol), if the heat of combustion of ethane, hydrogen and graphite is -1560, -393.5 and -286 kJ/mol, respectively, is ______.Correct answer is '-192.5'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard heat of formation () of ethane (in kJ/mol), if the heat of combustion of ethane, hydrogen and graphite is -1560, -393.5 and -286 kJ/mol, respectively, is ______.Correct answer is '-192.5'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard heat of formation () of ethane (in kJ/mol), if the heat of combustion of ethane, hydrogen and graphite is -1560, -393.5 and -286 kJ/mol, respectively, is ______.Correct answer is '-192.5'. Can you explain this answer?.
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