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Let A be a 3 × 3 matrix with eigenvalues, 1, –1 and 0. Then what is the determinant of I + A100?
    Correct answer is '4'. Can you explain this answer?
    Most Upvoted Answer
    Let A be a 3×3 matrix with eigenvalues, 1, –1 and 0. Then ...
    Eigenvalues of A = 1, –1 and 0
    Then, the eigenvalues of A100 are 1100, (–1)100 and (0)100.
    i.e. 1, +1 and 0
    And the eigenvalues of I + A100 are 1 + 1, 1 + 1 and 1 + 0.
    i.e. 2, 2 and 1
    Or |I + A100| = 2 × 2 × 1 = 4
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    Let A be a 3×3 matrix with eigenvalues, 1, –1 and 0. Then what is the determinant of I + A100?Correct answer is '4'. Can you explain this answer?
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