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In an adiabatic expansion of air (assume it is a mixture of nitrogen and oxygen) the volume increases by 5 percent, the percentage change in pressure is?
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In an adiabatic expansion of air (assume it is a mixture of nitrogen a...
I guess 5/ because... volume is directly proportional to pressure... and since the process is adiabatic.. the change in temperature is 0. this is just a blind guess. do let me know if this is wrong.
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In an adiabatic expansion of air (assume it is a mixture of nitrogen a...

Adiabatic Expansion of Air

Air, which is a mixture of nitrogen and oxygen, undergoes an adiabatic expansion when its volume increases without any heat exchange with the surroundings.

Percentage Change in Pressure

The percentage change in pressure during an adiabatic expansion can be calculated using the formula:

\[ \frac{\Delta P}{P} = \gamma \times \frac{\Delta V}{V} \]

where:
- \( \Delta P \) is the change in pressure
- \( P \) is the initial pressure
- \( \gamma \) is the adiabatic index (for air, it is approximately 1.4)
- \( \Delta V \) is the change in volume
- \( V \) is the initial volume

Given Data

In this case, the volume increases by 5 percent, so \( \frac{\Delta V}{V} = 0.05 \).

Calculating Percentage Change in Pressure

Substitute the given data into the formula:

\[ \frac{\Delta P}{P} = 1.4 \times 0.05 = 0.07 \]

Therefore, the percentage change in pressure during the adiabatic expansion of air is 7%. This means that the pressure of the air decreases by 7% as the volume increases by 5%.
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In an adiabatic expansion of air (assume it is a mixture of nitrogen and oxygen) the volume increases by 5 percent, the percentage change in pressure is?
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