A rocket fired vertically moves according to the relation s = at + b, where s is in kilometres and t in seconds. When it was observed from a point on the ground, which is at a distance of 3 km from the point of projection, it was found that at t = 1 second, the angle of elevation was 30anddeg; and at t = 2 seconds, the angle of elevation was 45anddeg;. Find the time at which the angle of elevation is 60anddeg;.a)(2 -3) secondsb)(1 +andradic;3)secondsc)(3 +andradic;3)secondsd)(2 +andradic;3)secondsCorrect answer is option 'D'. Can you explain this answer?

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A rocket fired vertically moves according to the relation s = at + b, where s is in kilometres and t in seconds. When it was observed from a point on the ground, which is at a distance of 3 km from the point of projection, it was found that at t = 1 second, the angle of elevation was 30° and at t = 2 seconds, the angle of elevation was 45°. Find the time at which the angle of elevation is 60°.

a)
(2 - 3) seconds
b)
(1 + √3) seconds
c)
(3 + √3) seconds
d)
(2 + √3) seconds

Correct answer is option 'D'. Can you explain this answer?

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A rocket fired vertically moves according to the relation s = at + b, ...

We know that the angle of elevation is the angle between the ground and the line of sight to the rocket.

Let's denote the height of the rocket at time t as h. Since the rocket is fired vertically, the horizontal distance from the point of projection to the point where it was observed is the same as the horizontal distance from the point of projection to the point on the ground. Therefore, at time t = 1 second, the horizontal distance is also 3 km.

Using trigonometry, we can set up the following equation:

tan(30) = h / 3

Rearranging the equation, we have:

h = 3 * tan(30)
h ≈ 1.732 km

Therefore, at t = 1 second, the height of the rocket is approximately 1.732 km.

Answered by Wizius Careers · View profile

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A rocket fired vertically moves according to the relation s = at + b, where s is in kilometres and t in seconds. When it was observed from a point on the ground, which is at a distance of 3 km from the point of projection, it was found that at t = 1 second, the angle of elevation was 30° and at t = 2 seconds, the angle of elevation was 45°. Find the time at which the angle of elevation is 60°.a)(2 -3) secondsb)(1 +√3)secondsc)(3 +√3)secondsd)(2 +√3)secondsCorrect answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about A rocket fired vertically moves according to the relation s = at + b, where s is in kilometres and t in seconds. When it was observed from a point on the ground, which is at a distance of 3 km from the point of projection, it was found that at t = 1 second, the angle of elevation was 30° and at t = 2 seconds, the angle of elevation was 45°. Find the time at which the angle of elevation is 60°.a)(2 -3) secondsb)(1 +√3)secondsc)(3 +√3)secondsd)(2 +√3)secondsCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A rocket fired vertically moves according to the relation s = at + b, where s is in kilometres and t in seconds. When it was observed from a point on the ground, which is at a distance of 3 km from the point of projection, it was found that at t = 1 second, the angle of elevation was 30° and at t = 2 seconds, the angle of elevation was 45°. Find the time at which the angle of elevation is 60°.a)(2 -3) secondsb)(1 +√3)secondsc)(3 +√3)secondsd)(2 +√3)secondsCorrect answer is option 'D'. Can you explain this answer?.

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