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Three point charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown in the figure. If the net electrostatic energy of the configuration is zero, then what is the value of 10×∣Q/q∣? [Take √2 =1.4]
    Correct answer is '6'. Can you explain this answer?
    Most Upvoted Answer
    Three point charges Q, +q and +q are placed at the vertices of a righ...
    Net electrostatic energy of the configuration will be
    Putting U = 0, we get
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    Three point charges Q, +q and +q are placed at the vertices of a righ...
    Given information:
    - The charges Q, q, and q are placed at the vertices of a right-angled isosceles triangle.
    - The net electrostatic energy of the configuration is zero.
    - The value of √2 is given as 1.4.

    To find:
    The value of 10×∣Q/q∣.

    Solution:

    Step 1: Understanding the configuration:
    - Let's assume that the length of each side of the isosceles triangle is 'a'.
    - The angle between the two equal sides of the triangle is 90 degrees.
    - The right angle is formed at the vertex where the charge Q is placed.
    - The other two vertices of the triangle have charges q and q.

    Step 2: Analyzing the electrostatic potential energy:
    - The electrostatic potential energy between two charges can be calculated using the formula:
    Potential energy = (k * Q * q) / r,
    where k is the electrostatic constant (9 × 10^9 Nm^2/C^2), Q and q are the magnitudes of the charges, and r is the distance between the charges.
    - In the given configuration, the net electrostatic energy is zero. This implies that the potential energy between every pair of charges is zero.

    Step 3: Calculating the distances:
    - Let's consider the distance between Q and q as d1, and the distance between q and q as d2.
    - Since the triangle is isosceles, the length of the perpendicular from the vertex with charge Q to the base of the triangle is (a/2).
    - Using Pythagoras theorem, we can calculate the distances d1 and d2 as:
    d1 = √[(a/2)^2 + (a/2)^2] = √(2 * (a/2)^2) = √(a^2/2) = a/√2
    d2 = a

    Step 4: Analyzing the potential energy equations:
    - We know that the potential energy between two charges is given by the equation:
    Potential energy = (k * Q * q) / r

    - Since the potential energy between every pair of charges is zero, we can write the following equations:
    (k * Q * q) / d1 = 0 (between Q and q)
    (k * q * q) / d2 = 0 (between q and q)

    - From these equations, we can conclude that either Q or q must be zero.
    - Since the value of Q is given, we can conclude that q must be zero.

    Step 5: Calculating the value of 10×∣Q/q∣:
    - Since q is zero, the value of Q/q is undefined.
    - Therefore, the value of 10×∣Q/q∣ is also undefined in this case.

    Conclusion:
    - Based on the given information and calculations, the value of 10×∣Q/q∣ is undefined, not '6' as mentioned in the question.
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    Three point charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown in the figure. If the net electrostatic energy of the configuration is zero, then what is the value of 10×∣Q/q∣? [Take √2 =1.4]Correct answer is '6'. Can you explain this answer?
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    Three point charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown in the figure. If the net electrostatic energy of the configuration is zero, then what is the value of 10×∣Q/q∣? [Take √2 =1.4]Correct answer is '6'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Three point charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown in the figure. If the net electrostatic energy of the configuration is zero, then what is the value of 10×∣Q/q∣? [Take √2 =1.4]Correct answer is '6'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Three point charges Q, +q and +q are placed at the vertices of a right-angled isosceles triangle as shown in the figure. If the net electrostatic energy of the configuration is zero, then what is the value of 10×∣Q/q∣? [Take √2 =1.4]Correct answer is '6'. Can you explain this answer?.
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