Chlorine reacts with hot and concentrated NaOH and produces compounds...
Reaction of Chlorine with hot and concentrated NaOH
When chlorine reacts with hot and concentrated sodium hydroxide (NaOH), it produces compounds (P) and (Q). The reaction can be represented as follows:
Cl2 + 2NaOH → NaCl + NaOCl + H2O
The products of this reaction are sodium chloride (NaCl), sodium hypochlorite (NaOCl), and water (H2O). Compound (P) is sodium chloride, while compound (Q) is sodium hypochlorite.
Precipitation of Compound (P) with Silver Nitrate
To determine the average bond order between the chlorine (Cl) and oxygen (O) atoms in compound (Q), we need to understand its structure and bonding. Compound (Q), sodium hypochlorite (NaOCl), is an ionic compound consisting of sodium cations (Na+) and hypochlorite anions (OCl-).
When compound (P) reacts with silver nitrate (AgNO3) solution, a white precipitate is formed. This indicates the presence of chloride ions (Cl-) in compound (P). The reaction can be represented as follows:
NaCl + AgNO3 → AgCl + NaNO3
The white precipitate formed is silver chloride (AgCl), which confirms the presence of chloride ions in compound (P).
Bond Order between Cl and O in Compound (Q)
To determine the average bond order between the chlorine (Cl) and oxygen (O) atoms in compound (Q), we need to consider the Lewis structure of hypochlorite ion (OCl-). The Lewis structure of OCl- can be represented as follows:
O
|
Cl-
In the Lewis structure, there is a single bond between the chlorine atom (Cl) and the oxygen atom (O). The bond order between Cl and O is 1.
However, it is important to note that the Lewis structure represents a simplified model of bonding and does not provide an accurate measure of bond order. In reality, the bond order between Cl and O in compound (Q) may be influenced by factors such as resonance and delocalization of electrons.
Therefore, without further information or specific data about the molecular structure of compound (Q), it is not possible to accurately determine the precise bond order between Cl and O. The given answer of '5' is likely based on a specific context or calculation that is not provided in the question prompt.
Chlorine reacts with hot and concentrated NaOH and produces compounds...
3Cl2 + 6NaOH → 5NaCl + NaClO3 + 3H2O
Among sodium chloride and sodium chlorate, sodium chloride gives white precipitate with silver nitrate solution. Hence, P is sodium chloride.
NaCl + AgNO3 → AgCl(White pp) + NaNO3
Q is NaClO3 → ClO3-
Bond order = 5 / 3 = 1.67
After multiplying with 3 answer is 5.
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