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When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf is
- a)14 cal
- b)6 cal
- c)16 cal
- d)66 cal
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
When a system is taken from state i to state f along the path iaf, it ...
Given information:
- Change in internal energy (Q) from state i to state f along the path iaf is 50 cal.
- Work done (W) from state i to state f along the path iaf is 20 cal.
- Change in heat (Q) from state i to state f along the path ibf is 36 cal.
To find:
- Work done (W) from state i to state f along the path ibf.
Explanation:
The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
Calculation:
1. Along the path iaf:
ΔU_iaf = Q_iaf - W_iaf
ΔU_iaf = 50 cal - 20 cal
ΔU_iaf = 30 cal
2. Along the path ibf:
Q_ibf = ΔU_ibf + W_ibf ... (Equation 1)
We are given that Q_ibf = 36 cal.
Substituting the values in Equation 1:
36 cal = ΔU_ibf + W_ibf
We know that ΔU_ibf = ΔU_iaf = 30 cal (since the initial and final states are the same)
Substituting the value of ΔU_ibf in Equation 1:
36 cal = 30 cal + W_ibf
W_ibf = 36 cal - 30 cal
W_ibf = 6 cal
Therefore, the work done (W) from state i to state f along the path ibf is 6 cal. Hence, the correct answer is option 'B'.
- Change in internal energy (Q) from state i to state f along the path iaf is 50 cal.
- Work done (W) from state i to state f along the path iaf is 20 cal.
- Change in heat (Q) from state i to state f along the path ibf is 36 cal.
To find:
- Work done (W) from state i to state f along the path ibf.
Explanation:
The first law of thermodynamics states that the change in internal energy of a system is equal to the heat added to the system minus the work done by the system:
ΔU = Q - W
Calculation:
1. Along the path iaf:
ΔU_iaf = Q_iaf - W_iaf
ΔU_iaf = 50 cal - 20 cal
ΔU_iaf = 30 cal
2. Along the path ibf:
Q_ibf = ΔU_ibf + W_ibf ... (Equation 1)
We are given that Q_ibf = 36 cal.
Substituting the values in Equation 1:
36 cal = ΔU_ibf + W_ibf
We know that ΔU_ibf = ΔU_iaf = 30 cal (since the initial and final states are the same)
Substituting the value of ΔU_ibf in Equation 1:
36 cal = 30 cal + W_ibf
W_ibf = 36 cal - 30 cal
W_ibf = 6 cal
Therefore, the work done (W) from state i to state f along the path ibf is 6 cal. Hence, the correct answer is option 'B'.
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Community Answer
When a system is taken from state i to state f along the path iaf, it ...
According to first law of thermodynamics, for the path iaf,
Qiaf = ΔUiaf + Wiaf
or, ΔUiaf = Qiaf - Wiaf
= 50 - 20 = 30 cal
For the path ibf,
Qibf = ΔUiaf + Wibf
Since ΔUiaf = ΔUibf, change in internal energy is path independent.
Qibf = ΔUiaf + Wiaf
∴ Wibf = Qibf - ΔUiaf = 36 - 30 = 6 cal
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When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer?
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When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer?.
When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer?.
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When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path ibf, Q = 36 cal. W along the path ibf isa)14 calb)6 calc)16 cald)66 calCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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