JEE Exam > JEE Questions > A parallel plate capacitor is made of two ci...
Start Learning for Free
A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close to
- a)6 × 104 C/m2
- b)6 × 10-7 C/m2
- c)3 × 10-7 C/m2
- d)3 × 104 C/m2
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A parallel plate capacitor is made of two circular plates separated b...
Here, dielectric constant, K = 2.2 and E = 3 × 104 V m-1
Electric field between the parallel plate capacitor with dielectric, E = σ / Kε0
So, charge density, σ = Kε0E = 2.2 × 8.85 × 10-12 × 3 × 104 = 5.8 × 10-7 or 6 × 10-7 C m-2.
Free Test
FREE
| Start Free Test |
Community Answer
A parallel plate capacitor is made of two circular plates separated b...
Concept:
The electric field between two plates of a parallel plate capacitor is given by:
E = σ/ε₀
where σ is the surface charge density on the plates, and ε₀ is the permittivity of free space. If a dielectric material is placed between the plates, the electric field is reduced by a factor of the dielectric constant of the material.
E = σ/(ε₀εᵣ)
where εᵣ is the relative permittivity or dielectric constant of the material.
Calculation:
Given: distance between the plates (d) = 5 mm = 0.005 m, electric field in the dielectric (E) = 3 × 10^4 V/m, dielectric constant (εᵣ) = 2.2
We know that the electric field between the plates of a parallel plate capacitor is given by:
E = σ/(ε₀εᵣ)
Rearranging the equation, we get:
σ = Eε₀εᵣ
Substituting the given values, we get:
σ = (3 × 10^4)(8.85 × 10^-12)(2.2)
σ = 5.934 × 10^-7 C/m^2
Therefore, the charge density of the positive plate is approximately 6 × 10^-7 C/m^2, which is option B.
The electric field between two plates of a parallel plate capacitor is given by:
E = σ/ε₀
where σ is the surface charge density on the plates, and ε₀ is the permittivity of free space. If a dielectric material is placed between the plates, the electric field is reduced by a factor of the dielectric constant of the material.
E = σ/(ε₀εᵣ)
where εᵣ is the relative permittivity or dielectric constant of the material.
Calculation:
Given: distance between the plates (d) = 5 mm = 0.005 m, electric field in the dielectric (E) = 3 × 10^4 V/m, dielectric constant (εᵣ) = 2.2
We know that the electric field between the plates of a parallel plate capacitor is given by:
E = σ/(ε₀εᵣ)
Rearranging the equation, we get:
σ = Eε₀εᵣ
Substituting the given values, we get:
σ = (3 × 10^4)(8.85 × 10^-12)(2.2)
σ = 5.934 × 10^-7 C/m^2
Therefore, the charge density of the positive plate is approximately 6 × 10^-7 C/m^2, which is option B.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer?
Question Description
A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer?.
A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer?.
Solutions for A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A parallel plate capacitor is made of two circular plates separated by a distance of 5 mm and with a dielectric of dielectric constant 2.2 between them. When the electric field in the dielectric is 3 × 104 V/m, the charge density of the positive plate will be close toa)6 × 104 C/m2b)6 × 10-7 C/m2c)3 × 10-7 C/m2d)3 × 104 C/m2Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup