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A box contains 100 tickets numbered 1 to 100. If 2 tickets are drawn successively without replacement from the box, what is the probability that all the tickets bear numbers divisible by 10?
  • a)
    0.04
  • b)
    0.4
  • c)
    0.001
  • d)
    0.009
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
A box contains 100 tickets numbered 1 to 100. If 2 tickets are drawn s...
No. of tickets numbered from 1 to 100, divisible by 10 = 10
Let,
Event (A) = Drawing 2 tickets successively without replacement which are divisible by 10.
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A box contains 100 tickets numbered 1 to 100. If 2 tickets are drawn successively without replacement from the box, what is the probability that all the tickets bear numbers divisible by 10?a)0.04b)0.4c)0.001d)0.009Correct answer is option 'D'. Can you explain this answer?
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A box contains 100 tickets numbered 1 to 100. If 2 tickets are drawn successively without replacement from the box, what is the probability that all the tickets bear numbers divisible by 10?a)0.04b)0.4c)0.001d)0.009Correct answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A box contains 100 tickets numbered 1 to 100. If 2 tickets are drawn successively without replacement from the box, what is the probability that all the tickets bear numbers divisible by 10?a)0.04b)0.4c)0.001d)0.009Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains 100 tickets numbered 1 to 100. If 2 tickets are drawn successively without replacement from the box, what is the probability that all the tickets bear numbers divisible by 10?a)0.04b)0.4c)0.001d)0.009Correct answer is option 'D'. Can you explain this answer?.
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