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Factorize polynomials x+ y +xy2+ x2y?
options:
a: (x-1)(x+y)
b: (x-1)(x-y)
c: (xy+1)(x+y)
d: (x+1)(x-y)?
options:
a: (x-1)(x+y)
b: (x-1)(x-y)
c: (xy+1)(x+y)
d: (x+1)(x-y)?
Most Upvoted Answer
Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y...
To factorize the given polynomials, we need to break down each term into its factors and then find the common factors among them. Let's factorize the given polynomials one by one:
1. x:
The polynomial x is already in its simplest form and cannot be factored further.
2. y:
Similar to x, the polynomial y is already in its simplest form and cannot be factored further.
3. xy^2:
This polynomial can be factored by taking out the common factor, which is y. Therefore, we can write it as y(x*y).
4. x^2y:
This polynomial can be factored by taking out the common factor, which is xy. Therefore, we can write it as xy(x).
Now, let's compare the factorizations with the given options:
a: (x-1)(x y)
b: (x-1)(x-y)
c: (xy 1)(x y)
d: (x 1)(x-y)
Comparing the factorizations with the given options, we can see that option b: (x-1)(x-y) matches the factorizations of xy^2 and x^2y.
Therefore, the correct factorization for the given polynomials is option b: (x-1)(x-y).
1. x:
The polynomial x is already in its simplest form and cannot be factored further.
2. y:
Similar to x, the polynomial y is already in its simplest form and cannot be factored further.
3. xy^2:
This polynomial can be factored by taking out the common factor, which is y. Therefore, we can write it as y(x*y).
4. x^2y:
This polynomial can be factored by taking out the common factor, which is xy. Therefore, we can write it as xy(x).
Now, let's compare the factorizations with the given options:
a: (x-1)(x y)
b: (x-1)(x-y)
c: (xy 1)(x y)
d: (x 1)(x-y)
Comparing the factorizations with the given options, we can see that option b: (x-1)(x-y) matches the factorizations of xy^2 and x^2y.
Therefore, the correct factorization for the given polynomials is option b: (x-1)(x-y).
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Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y)c: (xy+1)(x+y)d: (x+1)(x-y)?
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Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y)c: (xy+1)(x+y)d: (x+1)(x-y)? for Class 8 2024 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y)c: (xy+1)(x+y)d: (x+1)(x-y)? covers all topics & solutions for Class 8 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y)c: (xy+1)(x+y)d: (x+1)(x-y)?.
Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y)c: (xy+1)(x+y)d: (x+1)(x-y)? for Class 8 2024 is part of Class 8 preparation. The Question and answers have been prepared according to the Class 8 exam syllabus. Information about Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y)c: (xy+1)(x+y)d: (x+1)(x-y)? covers all topics & solutions for Class 8 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Factorize polynomials x+ y +xy2+ x2y?options:a: (x-1)(x+y)b: (x-1)(x-y)c: (xy+1)(x+y)d: (x+1)(x-y)?.
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