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Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?
- a)SOCI2; H2O
- b)SO2CI2; alc. KOH
- c)CI2/hv; H2O
- d)SOCI2; alc. KOH
Correct answer is option 'B'. Can you explain this answer?
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Which of the following sequences of reactions (reagents) can be used ...
Conversion of C6H5CH2CH3 into C6H5CH = CH2
To convert C6H5CH2CH3 into C6H5CH = CH2, we need to perform a series of reactions. Among the given options, the correct sequence of reactions is:
SO2Cl2; alc. KOH
Step 1: Reaction with SO2Cl2
C6H5CH2CH3 reacts with SO2Cl2 to form C6H5CH2CH2Cl.
Step 2: Reaction with alcoholic KOH
C6H5CH2CH2Cl reacts with alcoholic KOH to form C6H5CH = CH2.
Explanation:
Step 1: Reaction with SO2Cl2
When C6H5CH2CH3 is treated with SO2Cl2, it undergoes a nucleophilic substitution reaction due to the presence of a strong electrophile (SO2Cl2). The lone pair of electrons on the oxygen atom of SO2Cl2 attacks the carbon atom of the alkyl group in C6H5CH2CH3, resulting in the substitution of the ethyl group with a chlorine atom. This reaction is known as the Friedel-Crafts reaction.
Step 2: Reaction with alcoholic KOH
The product obtained from the previous step, C6H5CH2CH2Cl, is treated with alcoholic KOH. In this reaction, alcoholic KOH acts as a base and abstracts the acidic hydrogen from the carbon adjacent to the chlorine atom. This deprotonation results in the formation of an alkene, C6H5CH = CH2.
Overall Reaction:
The overall reaction can be represented as follows:
C6H5CH2CH3 + SO2Cl2 → C6H5CH2CH2Cl
C6H5CH2CH2Cl + alc. KOH → C6H5CH = CH2
This sequence of reactions allows us to convert C6H5CH2CH3 into C6H5CH = CH2 by selectively substituting the ethyl group with a chlorine atom and then eliminating HCl to form the desired alkene.
To convert C6H5CH2CH3 into C6H5CH = CH2, we need to perform a series of reactions. Among the given options, the correct sequence of reactions is:
SO2Cl2; alc. KOH
Step 1: Reaction with SO2Cl2
C6H5CH2CH3 reacts with SO2Cl2 to form C6H5CH2CH2Cl.
Step 2: Reaction with alcoholic KOH
C6H5CH2CH2Cl reacts with alcoholic KOH to form C6H5CH = CH2.
Explanation:
Step 1: Reaction with SO2Cl2
When C6H5CH2CH3 is treated with SO2Cl2, it undergoes a nucleophilic substitution reaction due to the presence of a strong electrophile (SO2Cl2). The lone pair of electrons on the oxygen atom of SO2Cl2 attacks the carbon atom of the alkyl group in C6H5CH2CH3, resulting in the substitution of the ethyl group with a chlorine atom. This reaction is known as the Friedel-Crafts reaction.
Step 2: Reaction with alcoholic KOH
The product obtained from the previous step, C6H5CH2CH2Cl, is treated with alcoholic KOH. In this reaction, alcoholic KOH acts as a base and abstracts the acidic hydrogen from the carbon adjacent to the chlorine atom. This deprotonation results in the formation of an alkene, C6H5CH = CH2.
Overall Reaction:
The overall reaction can be represented as follows:
C6H5CH2CH3 + SO2Cl2 → C6H5CH2CH2Cl
C6H5CH2CH2Cl + alc. KOH → C6H5CH = CH2
This sequence of reactions allows us to convert C6H5CH2CH3 into C6H5CH = CH2 by selectively substituting the ethyl group with a chlorine atom and then eliminating HCl to form the desired alkene.
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Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer?
Question Description
Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer?.
Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer?.
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Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Which of the following sequences of reactions (reagents) can be used for the conversion of C6H5CH2CH3 into C6H5CH = CH2?a)SOCI2; H2Ob)SO2CI2; alc. KOHc)CI2/hv; H2Od)SOCI2; alc. KOHCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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