The minimised form of Boolean logic expression (A’B’C&rsqu...
Given: A′B + ABC′ + BC’ + AB′C′
= A’B + BC’ (1 + A) + AB’C”
= A’B + BC’ + AB’C’
= A’B + BC’ + BC’ + AB’C’
= B(A’ + C’) + C’(A + AB’)
= B(AC)’ + C’ A(1 + B’)
= B(AC)’ + AC’.
The minimised form of Boolean logic expression (A’B’C&rsqu...
Understanding the Boolean Expression
To simplify the Boolean expression A’B’C’ + A’BC’ + A’BC + ABC’:
- Identify Variables: The variables involved are A, B, and C, with their respective complements (A’, B’, C’).
Step 1: Group Terms
- Group the terms based on common factors:
- A’B’C’ (all off)
- A’BC’ (A’ and C’ are common)
- A’BC (A’ common)
- ABC’ (B and C’ common)
Step 2: Factor Common Terms
- From the first two terms: A’B’C’ + A’BC’ = A’C’(B’ + B) = A’C’ (since B’ + B = 1)
- From the last two terms: A’BC + ABC’ = AC’ + A’B (after factoring)
Step 3: Combine the Results
- Combine the results from the previous step:
- Final expression = A’C’ + A’B + BC’
Final Simplified Expression
- The minimized form of the expression becomes:
- A’C’ + BC’ + A’B
Conclusion
- The correct simplified expression is A’C’ + BC’ + A’B, which matches option (a).
Thus, the minimized form of the given Boolean expression is indeed option A. This simplification demonstrates the effectiveness of Boolean algebra in reducing complex logic expressions.