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In the year 1648, if February had 5 Sundays, then what was the day on February 13, 1750?
- a)Sunday
- b)Friday
- c)Saturday
- d)Monday
- e)Thursday
Correct answer is option 'C'. Can you explain this answer?
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In the year 1648, if February had 5 Sundays, then what was the day on ...
Solution:
Finding the Day of February in 1648:
We know that 1648 was a leap year, which means it had 366 days. We can use the concept of odd days to find the day of February in 1648.
- 365 days have 1 odd day.
- 1 leap year has 2 odd days.
So, 1600 to 1648, there are 12 leap years and (1648 - 1600 - 12) = 36 ordinary years.
Number of odd days in 1600-1648 = 12 x 2 + 36 x 1 = 60 odd days.
60 odd days = (8 weeks + 4 odd days)
So, the day on February 1, 1648, was 4 days ahead of the day on January 1, 1648, which was a Saturday.
Finding the Number of Days between 1648 and 1750:
The number of years between 1648 and 1750 = 1750 - 1648 = 102 years.
We know that 100 years have 5 odd days.
So, 102 years have (5 odd days x 102 years) = 510 odd days.
510 odd days = (72 weeks + 6 odd days)
So, the day on February 1, 1750, was 6 days ahead of the day on February 1, 1648.
Finding the Day on February 13, 1750:
We know that February 1648 had 4 odd days and February 1750 had 6 odd days.
So, the number of odd days between February 1, 1648, and February 1, 1750, is (6 - 4) = 2.
As there are 7 days in a week, 2 odd days will be equal to 2 days.
So, the day on February 13, 1750, will be 2 days ahead of the day on February 1, 1750, which was a Saturday.
Hence, the answer is option (c) Saturday.
Finding the Day of February in 1648:
We know that 1648 was a leap year, which means it had 366 days. We can use the concept of odd days to find the day of February in 1648.
- 365 days have 1 odd day.
- 1 leap year has 2 odd days.
So, 1600 to 1648, there are 12 leap years and (1648 - 1600 - 12) = 36 ordinary years.
Number of odd days in 1600-1648 = 12 x 2 + 36 x 1 = 60 odd days.
60 odd days = (8 weeks + 4 odd days)
So, the day on February 1, 1648, was 4 days ahead of the day on January 1, 1648, which was a Saturday.
Finding the Number of Days between 1648 and 1750:
The number of years between 1648 and 1750 = 1750 - 1648 = 102 years.
We know that 100 years have 5 odd days.
So, 102 years have (5 odd days x 102 years) = 510 odd days.
510 odd days = (72 weeks + 6 odd days)
So, the day on February 1, 1750, was 6 days ahead of the day on February 1, 1648.
Finding the Day on February 13, 1750:
We know that February 1648 had 4 odd days and February 1750 had 6 odd days.
So, the number of odd days between February 1, 1648, and February 1, 1750, is (6 - 4) = 2.
As there are 7 days in a week, 2 odd days will be equal to 2 days.
So, the day on February 13, 1750, will be 2 days ahead of the day on February 1, 1750, which was a Saturday.
Hence, the answer is option (c) Saturday.
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In the year 1648, if February had 5 Sundays, then what was the day on February 13, 1750?a)Sundayb)Fridayc)Saturdayd)Mondaye)ThursdayCorrect answer is option 'C'. Can you explain this answer?
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