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ABC is an isosceles triangle. If the coordinates of the ends of the base are B (1, 3) and C (-2, 7), then the coordinates of vertex A are
- a)(1, 6)
- b)
- c)(5/6 , 6)
- d)(1/2 , 5)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
ABC is an isosceles triangle. If the coordinates of the ends of the ba...
The vertex A (x, y) is equidistant from B and C because ABC is an isosceles triangle.
Therefore, (x - 1)2 + (y - 3)2 = (x + 2)2 + (y - 7)2
⇒ 6x - 8y + 43 = 0
Now, from the options, we have
x = 5/6 and y = 6, which satisfy the above equation.
Therefore, (x - 1)2 + (y - 3)2 = (x + 2)2 + (y - 7)2
⇒ 6x - 8y + 43 = 0
Now, from the options, we have
x = 5/6 and y = 6, which satisfy the above equation.
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ABC is an isosceles triangle. If the coordinates of the ends of the base are B (1, 3) and C (-2, 7), then the coordinates of vertex A area)(1, 6)b)c)(5/6 , 6)d)(1/2 , 5)Correct answer is option 'C'. Can you explain this answer?
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