Find the area enclosed by |x| + |y| = 4.a)16 sq. unitsb)32 sq. unitsc)...
To find the area enclosed by the equation |x| + |y| = 4, we can split it into four separate cases:
1) When both x and y are positive:
In this case, the equation becomes x + y = 4.
The area enclosed by this equation is a right triangle with base 4 units and height 4 units.
The area of a triangle is given by A = (1/2) * base * height.
Therefore, the area of this triangle is (1/2) * 4 * 4 = 8 square units.
2) When both x and y are negative:
In this case, the equation becomes -x - y = 4.
This is the same equation as in case 1, just with negative values.
Therefore, the area of this triangle is also 8 square units.
3) When x is positive and y is negative:
In this case, the equation becomes x - y = 4.
The area enclosed by this equation is a right triangle with base 4 units and height 4 units.
Again, the area of this triangle is 8 square units.
4) When x is negative and y is positive:
In this case, the equation becomes -x + y = 4.
This is the same equation as in case 3, just with negative values.
Therefore, the area of this triangle is also 8 square units.
To find the total area enclosed by the equation |x| + |y| = 4, we add up the areas from all four cases: 8 + 8 + 8 + 8 = 32 square units.
Therefore, the correct answer is b) 32 sq. units.