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Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.?
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Two element A and B form compound of formula AB2 and AB4 when dissolve...
Given data:
- Two elements A and B form compound of formula AB2 and AB4
- 1.0g of AB2 lowers f.pt. by 23 degree centigrade when dissolved in 20.0g of benzene
- 1.0g of AB4 lowers f.pt. by 1.3 degree centigrade when dissolved in 20.0g of benzene
- Kf for benzene is 5.1
- Atomic masses of A and B are unknown
To solve for the atomic masses of A and B, we can use the formula:
ΔT = Kf x molality
where ΔT is the change in freezing point, Kf is the freezing point depression constant of benzene, and molality is the concentration of solute in moles per kilogram of solvent.
Calculating molality for AB2:
ΔT1 = 23°C
Kf = 5.1°C/m
w1 = 1.0g
w2 = 20.0g
m1 = w1 / M1
m2 = w2 / Msolvent
molality1 = (m1 / m2) x 1000
molality1 = (1 / (M1 / 1000)) / (20 / 1000)
molality1 = 50 / M1
Calculating molality for AB4:
ΔT2 = 1.3°C
Kf = 5.1°C/m
w1 = 1.0g
w2 = 20.0g
m1 = w1 / M2
m2 = w2 / Msolvent
molality2 = (m1 / m2) x 1000
molality2 = (1 / (M2 / 1000)) / (20 / 1000)
molality2 = 50 / M2
Since A and B combine to form AB2 and AB4, we can write:
2M1 + M2 = weight of AB2
M1 + 4M2 = weight of AB4
Let's solve for M1 and M2 by substituting the above equations and using molality values:
ΔT1 = Kf x molality1
23 = 5.1 x (50 / M1)
M1 = 110.86
ΔT2 = Kf x molality2
1.3 = 5.1 x (50 / M2)
M2 = 207.57
Therefore, the atomic masses of A and B are 110.86 and 207.57 respectively.
Conclusion:
- The atomic masses of A and B are 110.86 and 207.57 respectively
- We used the formula ΔT = Kf x molality to calculate the molality of AB2 and AB4
- We substituted the molality values in equations to solve for the atomic masses of A and B
- Two elements A and B form compound of formula AB2 and AB4
- 1.0g of AB2 lowers f.pt. by 23 degree centigrade when dissolved in 20.0g of benzene
- 1.0g of AB4 lowers f.pt. by 1.3 degree centigrade when dissolved in 20.0g of benzene
- Kf for benzene is 5.1
- Atomic masses of A and B are unknown
To solve for the atomic masses of A and B, we can use the formula:
ΔT = Kf x molality
where ΔT is the change in freezing point, Kf is the freezing point depression constant of benzene, and molality is the concentration of solute in moles per kilogram of solvent.
Calculating molality for AB2:
ΔT1 = 23°C
Kf = 5.1°C/m
w1 = 1.0g
w2 = 20.0g
m1 = w1 / M1
m2 = w2 / Msolvent
molality1 = (m1 / m2) x 1000
molality1 = (1 / (M1 / 1000)) / (20 / 1000)
molality1 = 50 / M1
Calculating molality for AB4:
ΔT2 = 1.3°C
Kf = 5.1°C/m
w1 = 1.0g
w2 = 20.0g
m1 = w1 / M2
m2 = w2 / Msolvent
molality2 = (m1 / m2) x 1000
molality2 = (1 / (M2 / 1000)) / (20 / 1000)
molality2 = 50 / M2
Since A and B combine to form AB2 and AB4, we can write:
2M1 + M2 = weight of AB2
M1 + 4M2 = weight of AB4
Let's solve for M1 and M2 by substituting the above equations and using molality values:
ΔT1 = Kf x molality1
23 = 5.1 x (50 / M1)
M1 = 110.86
ΔT2 = Kf x molality2
1.3 = 5.1 x (50 / M2)
M2 = 207.57
Therefore, the atomic masses of A and B are 110.86 and 207.57 respectively.
Conclusion:
- The atomic masses of A and B are 110.86 and 207.57 respectively
- We used the formula ΔT = Kf x molality to calculate the molality of AB2 and AB4
- We substituted the molality values in equations to solve for the atomic masses of A and B
Community Answer
Two element A and B form compound of formula AB2 and AB4 when dissolve...
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Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.?
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Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.?.
Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.?.
Solutions for Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.? in English & in Hindi are available as part of our courses for Class 11.
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Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.?, a detailed solution for Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.? has been provided alongside types of Two element A and B form compound of formula AB2 and AB4 when dissolved in 20.0g of benzene 1.0g of AB2 lowers f.pt. by 23 degree centigrate whereas 1.0g of AB4 lowers. f.pt. by 1.3 degree centigrate.The Kf for benzene is 5.1.The atomic masses of A and B are.plz give me ans with easy solution and formula.? theory, EduRev gives you an
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