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On a certain day, the cost of an article is 'a' rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is 'a' rupees again. If b = 20, what can be the value of 'a'?
- a)10
- b)15
- c)20
- d)25
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
On a certain day, the cost of an article is a rupees. The next day, it...
To solve this problem, let's break it down step by step:
Step 1: Initial cost of the article is a rupees.
Step 2: The cost increases by a% and then decreases by b% on the first day.
Step 3: The cost increases by a% and then decreases by b% on the second day.
Step 4: The cost returns to a rupees again.
Let's calculate the cost after each step:
Step 1: Initial cost = a rupees
Step 2: Increase by a% = a + (a/100)*a = a + a^2/100
Decrease by b% = (a + a^2/100) - (b/100)*(a + a^2/100) = (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
Step 3: Increase by a% = (a + a^2/100) + (a/100)*(a + a^2/100) = (a + a^2/100) + (a/100)*(a + a^2/100)
Decrease by b% = ((a + a^2/100) + (a/100)*(a + a^2/100)) - (b/100)*((a + a^2/100) + (a/100)*(a + a^2/100))
= ((a + a^2/100) + (a/100)*(a + a^2/100)) - (b/100)*((a + a^2/100) + (a/100)*(a + a^2/
Step 1: Initial cost of the article is a rupees.
Step 2: The cost increases by a% and then decreases by b% on the first day.
Step 3: The cost increases by a% and then decreases by b% on the second day.
Step 4: The cost returns to a rupees again.
Let's calculate the cost after each step:
Step 1: Initial cost = a rupees
Step 2: Increase by a% = a + (a/100)*a = a + a^2/100
Decrease by b% = (a + a^2/100) - (b/100)*(a + a^2/100) = (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
= (a + a^2/100) - (b/100)*(a + a^2/100)
Step 3: Increase by a% = (a + a^2/100) + (a/100)*(a + a^2/100) = (a + a^2/100) + (a/100)*(a + a^2/100)
Decrease by b% = ((a + a^2/100) + (a/100)*(a + a^2/100)) - (b/100)*((a + a^2/100) + (a/100)*(a + a^2/100))
= ((a + a^2/100) + (a/100)*(a + a^2/100)) - (b/100)*((a + a^2/100) + (a/100)*(a + a^2/
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On a certain day, the cost of an article is a rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is a rupees again. If b = 20, what can be the value of a?a)10b)15c)20d)25Correct answer is option 'D'. Can you explain this answer?
Question Description
On a certain day, the cost of an article is a rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is a rupees again. If b = 20, what can be the value of a?a)10b)15c)20d)25Correct answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about On a certain day, the cost of an article is a rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is a rupees again. If b = 20, what can be the value of a?a)10b)15c)20d)25Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a certain day, the cost of an article is a rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is a rupees again. If b = 20, what can be the value of a?a)10b)15c)20d)25Correct answer is option 'D'. Can you explain this answer?.
On a certain day, the cost of an article is a rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is a rupees again. If b = 20, what can be the value of a?a)10b)15c)20d)25Correct answer is option 'D'. Can you explain this answer? for CAT 2024 is part of CAT preparation. The Question and answers have been prepared according to the CAT exam syllabus. Information about On a certain day, the cost of an article is a rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is a rupees again. If b = 20, what can be the value of a?a)10b)15c)20d)25Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for CAT 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for On a certain day, the cost of an article is a rupees. The next day, it increases by a% and then decreases by b%. The next day again, it increases by a% and then decreases by b%. Now, the cost of the article is a rupees again. If b = 20, what can be the value of a?a)10b)15c)20d)25Correct answer is option 'D'. Can you explain this answer?.
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