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Two cells with the same e.m.f 'E' and different internal resistances r1 and r2 are connected in series to an external resistance R. The value of R so that the potential difference across the first cell be zero is
- a)√r1r2
- b)r1 + r2
- c)r1 - r2
- d)r1 + r2/2
Correct answer is option 'C'. Can you explain this answer?
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Most Upvoted Answer
Two cells with the same e.m.f E and different internal resistances r1 ...
R = (r1 + r2)
b) R = E/(r1 + r2)
c) R = (r1 - r2)
d) R = E/(r1 - r2)
The correct answer is b) R = E/(r1 + r2).
Explanation:
When two cells with the same e.m.f E and different internal resistances r1 and r2 are connected in series to an external resistance R, the total resistance in the circuit is R + r1 + r2. The current flowing through the circuit is given by:
I = E / (R + r1 + r2)
The potential difference across the first cell is given by:
V1 = E - I r1
For the potential difference across the first cell to be zero, we have:
E - I r1 = 0
Substituting the value of I, we get:
E - (E / (R + r1 + r2)) r1 = 0
Solving for R, we get:
R = E / ((r1 + r2))
Therefore, the value of R so that the potential difference across the first cell be zero is b) R = E/(r1 + r2).
b) R = E/(r1 + r2)
c) R = (r1 - r2)
d) R = E/(r1 - r2)
The correct answer is b) R = E/(r1 + r2).
Explanation:
When two cells with the same e.m.f E and different internal resistances r1 and r2 are connected in series to an external resistance R, the total resistance in the circuit is R + r1 + r2. The current flowing through the circuit is given by:
I = E / (R + r1 + r2)
The potential difference across the first cell is given by:
V1 = E - I r1
For the potential difference across the first cell to be zero, we have:
E - I r1 = 0
Substituting the value of I, we get:
E - (E / (R + r1 + r2)) r1 = 0
Solving for R, we get:
R = E / ((r1 + r2))
Therefore, the value of R so that the potential difference across the first cell be zero is b) R = E/(r1 + r2).
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