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Consider two observers moving with respect to each other at a speed v along a straight line. They observe a block of mass moving over a distance l on a rough surface. The following quantities will be same as observed by the two observers
- a)Kinetic energy of the block at time t
- b)Work done by friction
- c)Total work done on the block
- d)Acceleration of the block
Correct answer is option 'D'. Can you explain this answer?
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Consider two observers moving with respect to each other at a speedv a...
The Principle of Relativity:
The principle of relativity states that the laws of physics are the same for all observers in uniform motion relative to each other. In other words, the physical laws and phenomena do not depend on the motion of the observer. This principle forms the basis for understanding the behavior of objects in different reference frames.
Analysis of the Given Situation:
In this scenario, we have two observers moving with respect to each other at a speed v along a straight line. They observe a block of mass moving over a distance on a rough surface. We need to determine which quantities will be the same as observed by the two observers.
Kinetic Energy of the Block at Time t:
The kinetic energy of an object is given by the formula KE = 1/2 mv^2, where m is the mass of the object and v is its velocity. In this case, both observers will measure the same mass and velocity of the block since these quantities are independent of the observer's motion. Therefore, the kinetic energy of the block at time t will be the same for both observers.
Work Done by Friction:
The work done by friction can be calculated using the formula W = Fd, where F is the force of friction and d is the distance over which the force is applied. The force of friction depends on the normal force and the coefficient of friction, both of which are independent of the observer's motion. The distance traveled by the block will also be the same for both observers. Therefore, the work done by friction will be the same for both observers.
Total Work Done on the Block:
The total work done on an object is the sum of the work done by all the forces acting on it. In this case, the only force doing work on the block is the force of friction. Since the work done by friction is the same for both observers, the total work done on the block will also be the same for both observers.
Acceleration of the Block:
The acceleration of an object can be calculated using the formula a = F/m, where F is the net force acting on the object and m is its mass. In this scenario, the net force on the block is the force of friction. As discussed earlier, the force of friction is the same for both observers. Therefore, the acceleration of the block will be the same for both observers.
Conclusion:
In conclusion, the kinetic energy of the block, work done by friction, total work done on the block, and acceleration of the block will all be the same for both observers. This is in accordance with the principle of relativity, which states that the laws of physics are the same for all observers in uniform motion relative to each other.
The principle of relativity states that the laws of physics are the same for all observers in uniform motion relative to each other. In other words, the physical laws and phenomena do not depend on the motion of the observer. This principle forms the basis for understanding the behavior of objects in different reference frames.
Analysis of the Given Situation:
In this scenario, we have two observers moving with respect to each other at a speed v along a straight line. They observe a block of mass moving over a distance on a rough surface. We need to determine which quantities will be the same as observed by the two observers.
Kinetic Energy of the Block at Time t:
The kinetic energy of an object is given by the formula KE = 1/2 mv^2, where m is the mass of the object and v is its velocity. In this case, both observers will measure the same mass and velocity of the block since these quantities are independent of the observer's motion. Therefore, the kinetic energy of the block at time t will be the same for both observers.
Work Done by Friction:
The work done by friction can be calculated using the formula W = Fd, where F is the force of friction and d is the distance over which the force is applied. The force of friction depends on the normal force and the coefficient of friction, both of which are independent of the observer's motion. The distance traveled by the block will also be the same for both observers. Therefore, the work done by friction will be the same for both observers.
Total Work Done on the Block:
The total work done on an object is the sum of the work done by all the forces acting on it. In this case, the only force doing work on the block is the force of friction. Since the work done by friction is the same for both observers, the total work done on the block will also be the same for both observers.
Acceleration of the Block:
The acceleration of an object can be calculated using the formula a = F/m, where F is the net force acting on the object and m is its mass. In this scenario, the net force on the block is the force of friction. As discussed earlier, the force of friction is the same for both observers. Therefore, the acceleration of the block will be the same for both observers.
Conclusion:
In conclusion, the kinetic energy of the block, work done by friction, total work done on the block, and acceleration of the block will all be the same for both observers. This is in accordance with the principle of relativity, which states that the laws of physics are the same for all observers in uniform motion relative to each other.
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Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer?
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Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer?.
Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer?.
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Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Consider two observers moving with respect to each other at a speedv along a straight line. They observe a block of mass moving over a distancel on a rough surface. The following quantities will be same as observed by the two observersa)Kinetic energy of the block at time tb)Work done by frictionc)Total work done on the blockd)Acceleration of the blockCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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