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A capacitor of capacity C₁ is charged by connecting it across a battery of e.m.f. V₀. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity C₂. The potential difference across this combination is
- a)C₂/C₁ + C₂ V₀
- b)C₁/C₁ + C₂ V₀
- c)C₁ + C₂/C₂ V₀
- d)C₁ + C₂/C₁ V₀
Correct answer is option 'B'. Can you explain this answer?
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A capacitor of capacity C is charged by connecting it across a battery...
Given: A capacitor of capacity C is charged by connecting it across a battery of e.m.f. V.
To find: The potential difference across the combination of capacitors when it is connected in parallel with an uncharged capacitor of capacity C.
Solution:
When the capacitor is charged, it stores energy in the form of electric field across its plates. Let the charge on the capacitor be Q and the potential difference across its plates be V.
Q = CV
Energy stored in the capacitor, U = 1/2 CV²
When the charged capacitor is connected in parallel with an uncharged capacitor of the same capacity, the charge will distribute across both capacitors according to their capacitances.
The total capacitance of the combination is 2C, and the charge on the combination is Q.
The potential difference across the combination is given by:
V' = Q/(2C)
Substituting Q = CV, we get:
V' = CV/(2C)
V' = V/2
Therefore, the potential difference across the combination of capacitors when it is connected in parallel with an uncharged capacitor of capacity C is V/2.
Hence, option B is the correct answer.
To find: The potential difference across the combination of capacitors when it is connected in parallel with an uncharged capacitor of capacity C.
Solution:
When the capacitor is charged, it stores energy in the form of electric field across its plates. Let the charge on the capacitor be Q and the potential difference across its plates be V.
Q = CV
Energy stored in the capacitor, U = 1/2 CV²
When the charged capacitor is connected in parallel with an uncharged capacitor of the same capacity, the charge will distribute across both capacitors according to their capacitances.
The total capacitance of the combination is 2C, and the charge on the combination is Q.
The potential difference across the combination is given by:
V' = Q/(2C)
Substituting Q = CV, we get:
V' = CV/(2C)
V' = V/2
Therefore, the potential difference across the combination of capacitors when it is connected in parallel with an uncharged capacitor of capacity C is V/2.
Hence, option B is the correct answer.
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A capacitor of capacity C is charged by connecting it across a battery of e.m.f. V. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity C. The potential difference across this combination isa)C/C + C Vb)C/C + C Vc)C + C/C Vd)C + C/C VCorrect answer is option 'B'. Can you explain this answer?
Question Description
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ample number of questions to practice A capacitor of capacity C is charged by connecting it across a battery of e.m.f. V. The battery is then removed and the capacitor is connected in parallel with an uncharged capacitor of capacity C. The potential difference across this combination isa)C/C + C Vb)C/C + C Vc)C + C/C Vd)C + C/C VCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
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