A charged particle moves through a magnetic field in a direction perpe...
Magnetic Field and Charged Particles
When a charged particle moves through a magnetic field, it experiences a force perpendicular to both its velocity and the magnetic field. This force is given by the equation:
F = q(v x B)
where F is the force on the particle, q is the charge of the particle, v is the velocity of the particle, and B is the magnetic field.
Explanation of Options
a) Speed of the Particle Remains Unchanged
The force on the particle is always perpendicular to its velocity. This means that the force cannot change the speed of the particle, but it can change the direction of the velocity. Therefore, option 'A' is correct.
b) Direction of the Particle Remains Unchanged
As mentioned above, the force on the particle is perpendicular to its velocity. This means that the force can change the direction of the velocity, but it cannot change the speed. Therefore, option 'B' is incorrect.
c) Acceleration Remains Unchanged
The force on the particle can cause it to accelerate, since acceleration is defined as a change in velocity. However, the direction of the acceleration is always perpendicular to the direction of the velocity. Therefore, the acceleration vector is always changing direction, even if the magnitude remains constant. Therefore, option 'C' is incorrect.
d) Velocity Remains Unchanged
As mentioned above, the force on the particle is always perpendicular to its velocity. This means that the force can change the direction of the velocity, but it cannot change the speed. Therefore, option 'D' is incorrect.
Conclusion
When a charged particle moves through a magnetic field, the force on the particle is always perpendicular to its velocity. This means that the force cannot change the speed of the particle, but it can change the direction of the velocity. Therefore, the correct answer is option 'A'.
A charged particle moves through a magnetic field in a direction perpe...
Explanation:
When a charged particle moves through a magnetic field in a direction perpendicular to it, the magnetic force acts on the particle. This force is always perpendicular to the direction of motion of the particle and the magnetic field.
The strength of the force depends on the magnitude of the charge, the velocity of the particle, and the strength and direction of the magnetic field. The formula for the magnetic force on a charged particle is given by:
F = qVBsinθ
Where F is the magnetic force, q is the charge of the particle, V is the velocity of the particle, B is the strength of the magnetic field, and θ is the angle between the velocity vector and the magnetic field vector.
Now, let's consider the options given in the question:
a) Speed of the particle remains unchanged:
The magnetic force acting on the charged particle is perpendicular to the direction of motion of the particle. This means that the force does not do any work on the particle. Therefore, the kinetic energy of the particle remains constant, and hence its speed remains unchanged.
b) Direction of the particle remains unchanged:
As we have seen earlier, the magnetic force is always perpendicular to the direction of motion of the charged particle. Therefore, it does not change the direction of the particle.
c) Acceleration remains unchanged:
The magnetic force on the charged particle is given by:
F = ma
where m is the mass of the particle and a is its acceleration. Since the force is perpendicular to the velocity of the particle, it does not change its speed or direction. This means that the acceleration of the particle remains constant in magnitude and direction.
d) Velocity remains unchanged:
As we have seen earlier, the magnetic force does not change the speed or direction of the charged particle. Therefore, its velocity remains unchanged.
From the above explanations, it is clear that option 'A' is the correct answer.
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