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The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer?.

Solutions for The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.

Here you can find the meaning of The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer?, a detailed solution for The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice The standard Gibbs free energy change and enthalpy change at 25oC for the liquid phase reactionare given as ΔG0298= -4650 J/mol and ΔH0298= -3640 J/mol. If the solution is ideal and enthalpy change is assumed to be constant, then the equilibrium constant at 95oC isa)0.65b)4.94c)6.54d)8.65Correct answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.