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Five men and four women are to be seated on 9 adjacent seats in a cinema hall in such a way that no two women sit together. Find the number of ways in which they can be arranged.
  • a)
    43200
  • b)
    42100
  • c)
    39560
  • d)
    6! x 4!
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
Five men and four women are to be seated on 9 adjacent seats in a cine...
Given: Five men and four women are to be seated on 9 adjacent seats in a cinema hall in such a way that no two women sit together.

To solve this problem, we can use the principle of permutations and combinations.

Step 1: We can first arrange the five men in 5! ways.

Step 2: Now, we need to arrange the four women in such a way that no two women sit together. To do this, we can think of the women as 'dividers' between the men. We have 6 gaps between the men where we can place these dividers so that no two women sit together. This is because if we place all four women in one gap, then two of them will sit together. Therefore, we need to choose 4 gaps from the 6 gaps available and arrange the women in these gaps.

Number of ways to choose 4 gaps from 6 gaps = 6C4 = 15

Number of ways to arrange the four women in these gaps = 4!

Therefore, total number of ways to arrange the five men and four women = 5! x 15 x 4! = 43,200

Hence, option A is the correct answer.
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