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There are two dice; red and green. What is the probability that on roll the red die throws up a prime number which is divisible by the number thrown up on the roll of the green die?  
  • a)
    13/36
  • b)
    1/3
  • c)
    1/6
  • d)
    7/18
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
There are two dice; red and green. What is the probability that on rol...
To find the probability that the red die throws a prime number divisible by the number thrown on the green die, we need to consider all possible outcomes and count the favorable outcomes.

Let's first determine all the possible outcomes when rolling the red and green dice. Each die has 6 faces, so there are a total of 6 × 6 = 36 possible outcomes.

Favorable outcomes:
To determine the favorable outcomes, we need to find the prime numbers and their divisors. The prime numbers less than or equal to 6 are 2, 3, 5. Let's consider each prime number and find its divisors.

- Prime number 2: Divisors are 1 and 2.
- Prime number 3: Divisors are 1 and 3.
- Prime number 5: Divisors are 1 and 5.

Total favorable outcomes = (Number of prime numbers) × (Number of divisors) = 3 × 2 = 6

Therefore, there are 6 favorable outcomes.

Calculating the probability:
Probability = (Number of favorable outcomes) / (Total number of possible outcomes)

Probability = 6 / 36 = 1 / 6

Hence, the correct answer is option C) 1/6.
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There are two dice; red and green. What is the probability that on roll the red die throws up a prime number which is divisible by the number thrown up on the roll of the green die?a)13/36b)1/3c)1/6d)7/18Correct answer is option 'C'. Can you explain this answer?
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