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A colourless liquid at room temperature reacts with soda lime to form sodium salt of carboxylic acid and ammonia gas.The liquid is
- a)Propamamide
- b)Propanic acid
- c)Formamide
- d)Methyl ethanoate
Correct answer is option 'C'. Can you explain this answer?
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A colourless liquid at room temperature reacts with soda lime to form ...
The given information suggests that a colourless liquid reacts with soda lime to form the sodium salt of carboxylic acid and ammonia gas. We have to identify the liquid among the given options.
The reaction with soda lime indicates that the liquid is an amide. Soda lime is a mixture of sodium hydroxide and calcium oxide. When an amide reacts with soda lime, it undergoes a deamination reaction, producing the sodium salt of carboxylic acid and ammonia gas.
Now, let's look at the given options:
a) Propamamide - This is an amide, but it is not a primary amide. Primary amides undergo deamination with soda lime, whereas secondary and tertiary amides undergo different reactions. Therefore, propamamide is not the correct option.
b) Propanic acid - This is a carboxylic acid, not an amide. Therefore, it is not the correct option.
c) Formamide - This is a primary amide, which can undergo deamination with soda lime to form the sodium salt of carboxylic acid and ammonia gas. Therefore, formamide is the correct option.
d) Methyl ethanoate - This is an ester, not an amide. Therefore, it is not the correct option.
Hence, the correct option is c) Formamide.
The reaction with soda lime indicates that the liquid is an amide. Soda lime is a mixture of sodium hydroxide and calcium oxide. When an amide reacts with soda lime, it undergoes a deamination reaction, producing the sodium salt of carboxylic acid and ammonia gas.
Now, let's look at the given options:
a) Propamamide - This is an amide, but it is not a primary amide. Primary amides undergo deamination with soda lime, whereas secondary and tertiary amides undergo different reactions. Therefore, propamamide is not the correct option.
b) Propanic acid - This is a carboxylic acid, not an amide. Therefore, it is not the correct option.
c) Formamide - This is a primary amide, which can undergo deamination with soda lime to form the sodium salt of carboxylic acid and ammonia gas. Therefore, formamide is the correct option.
d) Methyl ethanoate - This is an ester, not an amide. Therefore, it is not the correct option.
Hence, the correct option is c) Formamide.
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A colourless liquid at room temperature reacts with soda lime to form sodium salt of carboxylic acid and ammonia gas.The liquid isa)Propamamideb)Propanic acidc)Formamided)Methyl ethanoateCorrect answer is option 'C'. Can you explain this answer?
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