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In a Young's experiment, two coherent sources are placed 0.90 mm apart and the fringes are observed one metre away. If it produces the second dark fringe at a distance of 1 mm from the central fringe, the wavelength of monochromatic light used would be
  • a)
    60 x 10−4 cm
  • b)
    10 x 10−4 cm
  • c)
    10 x 10−5 cm
  • d)
    6 x 10−5 cm
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
In a Youngs experiment, two coherent sources are placed 0.90 mmapart a...
To solve this problem, we can use the formula for the fringe separation in a Young's experiment:

Δy = λL / d

Where:
Δy is the fringe separation
λ is the wavelength of the light
L is the distance from the sources to the observation screen
d is the distance between the sources

In this case, we are given that the fringe separation is 1 mm (0.001 m), L is 1 m, and d is 0.90 mm (0.00090 m).

Plugging in these values into the formula, we can solve for λ:

0.001 = λ * 1 / 0.00090

Rearranging the equation, we get:

λ = 0.001 * 0.00090 / 1

λ = 0.0000009 m

Expressing this in scientific notation, we get:

λ = 9 x 10^-7 m

Therefore, the wavelength of the monochromatic light used in the Young's experiment is approximately 9 x 10^-7 m.
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In a Youngs experiment, two coherent sources are placed 0.90 mmapart a...
Distance of nth dark fringe from central fringe
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In a Youngs experiment, two coherent sources are placed 0.90 mmapart and the fringes are observed one metre away. If it produces the second dark fringe at a distance of 1 mmfrom the central fringe, the wavelength of monochromatic light used would bea)60 x 10−4 cmb)10 x 10−4 cmc)10 x 10−5cmd)6 x 10−5cmCorrect answer is option 'D'. Can you explain this answer?
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