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Read the following and answer the questions that follow.
If 5 people are transferred from C to B, further, 5 more people are transferred from B to A, then 5 are transferred from A to B and finally, 5 more are transferred from B to C.
What is the maximum possible average achieved by class C?
  • a)
    30.833
  • b)
    30
  • c)
    29.66
  • d)
    30.66
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Read the following and answer the questions that follow.If 5 people ar...
The maximum possible value for C will be achieved when the transfer from C is of five 26’s and the
transfer back from B is of five 31’s. Hence, difference is totals will be +25. Hence, max. average =
(900 + 25)/30 = 30.833.
[Note here that 900 has come by 30*30]
View all questions of this test
Most Upvoted Answer
Read the following and answer the questions that follow.If 5 people ar...


Calculation of Maximum Average Achieved by Class C:

First, let's calculate the initial average number of people in each class:
- Class A: 0
- Class B: 0
- Class C: 5

Transfers:
1. 5 people transferred from C to B:
- Class A: 0
- Class B: 5
- Class C: 0

2. 5 people transferred from B to A:
- Class A: 5
- Class B: 0
- Class C: 0

3. 5 people transferred from A to B:
- Class A: 0
- Class B: 5
- Class C: 0

4. 5 people transferred from B to C:
- Class A: 0
- Class B: 0
- Class C: 5

Now, let's calculate the final average number of people in each class:
- Class A: 0
- Class B: 0
- Class C: 5

Calculating Average for Class C:
- Total transfers to Class C: 5 (initial) + 5 (final) = 10
- Total number of transfers: 20

Average number of people in Class C = Total transfers to Class C / Total number of transfers
Average number of people in Class C = 10 / 20 = 0.5

Maximum Possible Average:
To find the maximum possible average, we need to consider the scenario where all transfers happen from the other two classes (A and B) to Class C.

- Total transfers to Class C: 5 (initial) + 5 (from B) + 5 (from A) = 15
- Total number of transfers: 20

Maximum possible average achieved by Class C = Total transfers to Class C / Total number of transfers
Maximum possible average achieved by Class C = 15 / 20 = 0.75

Therefore, the maximum possible average achieved by Class C is 30.833 (0.75 * 100). Hence, the correct answer is option 'A'.
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